CODEWITHSUNDEEP
phpmysql
davidian
davidian

Reputation: 35

MYSQL update not working with php variable id

I'm stuck on a simple MYSQL UPDATE statement; selecting an ID from the database, and then updating a record WHERE ID = $ID. Code:

$searchDates = ('SELECT * FROM booking_event WHERE subject != "Closed" AND is_reminded IS NULL AND DATE_ADD(NOW(), INTERVAL 2 DAY) >= `starting_date_time` AND NOW() <= `starting_date_time`'); 

$result = mysql_query($searchDates) or die (mysql_error());

while ($row = mysql_fetch_array($result)) {
  $id = $row['event_id'];

mysql_query("UPDATE booking_event SET is_reminded = 1 WHERE event_id = '$id'") or die (mysql_error()); 

}

For some reason it won't update with the ID selected from the database - I've tried using a testID variable and it works fine.

Any help would be appreciated Thanks!

Upvotes: 0

Views: 174

Answers (2)

Hugo Delsing
Hugo Delsing

Reputation: 14163

PHP variables are case sensitive. Most likely your column name in MYSQL will be something like Event_Id or any other casing. Using SELECT * will return the actual name, so to fetch it you would need $id = $row['Event_Id'];

Best thing to be sure you dont have a casing problem, use:

SELECT event_id FROM ....

and then $id = $row['event_id']; will work.

Upvotes: 1

Mahmoud Gamal
Mahmoud Gamal

Reputation: 79919

You can do this in one query like so:

UPDATE booking_event b1
INNER JOIN
(
    SELECT * 
    FROM booking_event 
    WHERE subject != "Closed" 
      AND is_reminded IS NULL 
      AND DATE_ADD(NOW(), INTERVAL 2 DAY) >= starting_date_time 
      AND NOW() <= starting_date_time
) b2
SET t1.is_reminded = 1 WHERE b1.event_id = b2.event_id

Upvotes: 2

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