Reputation: 3673
Can anyone help me compare an Integer to a Double using generics?
This is what I have:
public static <T extends Comparable<? super T>> int compare(T arg1, T arg2)
{
return arg1.compareTo(arg2);
}
public static void main(String[] args)
{
Number i = new Integer(5);
Number j = new Double(7);
System.out.println(GenericsTest.compare(i, j));
}
The error message I get is: Bound mismatch: The generic method compare(T, T) of type GenericsTest is not applicable for the arguments (Number, Number). The inferred type Number is not a valid substitute for the bounded parameter >
Upvotes: 4
Views: 6544
Reputation: 14309
The idea of this solution is to widen to BigDecimal
and then compare the two numbers (now is cleaner but somehow formatting doesn't work). Note you may reuse this static comparator without having to cast to double anywhere else. In the implementation you do need conversion to double not to lose information, basically you widen to the most general representation.
private static final Comparator<Number> NUMBER_COMPARATOR = new Comparator<Number>() {
private BigDecimal createBigDecimal(Number value) {
BigDecimal result = null;
if (value instanceof Short) {
result = BigDecimal.valueOf(value.shortValue());
} else
if (value instanceof Long) {
result = BigDecimal.valueOf(value.longValue());
} else
if (value instanceof Float) {
result = BigDecimal.valueOf(value.floatValue());
} else
if (value instanceof Double) {
result = BigDecimal.valueOf(value.doubleValue());
} else
if (value instanceof Integer) {
result = BigDecimal.valueOf(value.intValue());
} else {
throw new IllegalArgumentException("unsupported Number subtype: " + value.getClass().getName());
}
assert(result != null);
return result;
}
public int compare(Number o1, Number o2) {
return createBigDecimal(o1).compareTo(createBigDecimal(o2));
};
};
public static void main(String[] args) {
Number i = Integer.valueOf(5);
Number j = Double.valueOf(7);
// -1
System.out.println(NUMBER_COMPARATOR.compare(i, j));
i = Long.MAX_VALUE;
j = Long.valueOf(7);
// +1
System.out.println(NUMBER_COMPARATOR.compare(i, j));
i = Long.MAX_VALUE;
j = Long.valueOf(-7);
// +1
System.out.println(NUMBER_COMPARATOR.compare(i, j));
i = Long.MAX_VALUE;
j = Double.MAX_VALUE;
// -1
System.out.println(NUMBER_COMPARATOR.compare(i, j));
i = Long.MAX_VALUE;
j = Long.valueOf(Long.MAX_VALUE - 1);
// +1
System.out.println(NUMBER_COMPARATOR.compare(i, j));
// sorting Long values
Long[] values = new Long[] {Long.valueOf(10), Long.valueOf(-1), Long.valueOf(4)};
Arrays.sort(values, NUMBER_COMPARATOR);
// [-1, 4, 10]
System.out.println(Arrays.toString(values));
}
Upvotes: 6
Reputation: 61
private boolean compareObject(Object expected, Object actual) {
if (expected instanceof Number && actual instanceof Number) {
double e = ((Number) expected).doubleValue();
double a = ((Number) actual).doubleValue();
return e == a;
} else {
return com.google.common.base.Objects.equal(expected, actual);
}
}
Upvotes: 0
Reputation: 2812
Create a class that implements Comparable which takes a Number in the constructor. e.g.
public class GenericNumber implements Comparable<GenericNumber> {
private Number num;
public GenericNumber(Number num) {
this.num = num;
}
// write compare function that compares num member of two
// GenericNumber instances
}
Then simply do this:
GenericNumber i = new GenericNumber(new Integer(5));
GenericNumber j = new GenericNumber(new Double(7));
System.out.println(GenericsTest.compare(i,j));
Upvotes: -1
Reputation: 424993
Number doesn't implement Comparable.
Declare both variables as Integer.
Upvotes: 1
Reputation: 15641
As aready said in the comments, Number
does not implement Comparable
.
But Double
and Integer
do.
One way to make this work is like this:
public static <T extends Comparable<? super T>> int compare(T arg1, T arg2)
{
return arg1.compareTo(arg2);
}
public static void main(String[] args)
{
Double i = new Integer(5).doubleValue();
Double j = new Double(7);
System.out.println(GenericsTest.compare(i, j));
}
Upvotes: 1