CODEWITHSUNDEEP
pythonargv
camihan
camihan

Reputation: 57

issue with float from argv

I'm having a hard time converting a passed in argv[1] to a float number. I have been trying to basically pass in any int followed by a decimal and have it round up/down to the nearest whole number. (basic starter python project) I have been trying to play with float for a bit now and just cant figure it out. 

import sys

x = int(sys.argv[1])
num = x + .5
s = str(num())
point = s.find('.')
print s[:point]

if __name__ == "__main__":
    x(int(sys.argv[1]))

Edit(current code, after coffee and cleanup):

import sys

def x(argument):
    num = argument + .5
    s = str(num())
    point = s.find('.')
    print s[:point]

if __name__ == "__main__":
    x(int(round(float(sys.argv[1]))))

Finalized code(credit goes to: NPE)

import sys

def x(argument):
    print "Passed in value: " + str(argument)
    num = argument + .5
    print "Rounded whole number: " + str(int(num))

if __name__ == "__main__":
    x(float(sys.argv[1]))

Upvotes: 2

Views: 10853

Answers (1)

NPE
NPE

Reputation: 500257

It sounds like you're looking for either

val = round(float(sys.argv[1]))

or

val = int(round(float(sys.argv[1])))

depending on what you're expecting the type of val to be.

Upvotes: 4

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