CODEWITHSUNDEEP
xmlgroovy
rhellem
rhellem

Reputation: 869

Groovy and XML: Not able to insert processing instruction

Scenario

Need to update some attributes in an existing XML-file. The file contains a XSL processing instruction, so when the XML is parsed and updated I need to add the instruction before writing it to a file again. Problem is - whatever I do - I'm not able to insert the processing instruction

Based on the Java-example found at rgagnon.com I have created the code below

Example code ##

import groovy.xml.*

def xml = '''|<something>
            |  <Settings>
            |  </Settings>
            |</something>'''.stripMargin()

def document = DOMBuilder.parse( new StringReader( xml ) )
def pi = document.createProcessingInstruction('xml-stylesheet', 'type="text/xsl"    href="Bp8DefaultView.xsl"');
document.insertBefore(pi, document.documentElement) 

println document.documentElement

Creates output 

<?xml version="1.0" encoding="UTF-8"?>
<something>
  <Settings>
  </Settings>
</something>

What I want

<?xml version="1.0" encoding="UTF-8"?>
<?xml-stylesheet type="text/xsl" href="Bp8DefaultView.xsl"?>
<something>
  <Settings>
  </Settings>
</something>

Upvotes: 0

Views: 815

Answers (1)

Ian Roberts
Ian Roberts

Reputation: 122394

You're inserting the PI before the documentElement, but then passing only the element to println. Does it work if you print the whole document?

Failing that, the "official" way to output a DOM document is to use LSSerializer

def ser = document.implementation.createLSSerializer()
new File("output.xml").withOutputStream { o ->
  def lso = document.implementation.createLSOutput()
  lso.byteStream = o
  ser.write(document, lso)
}

Upvotes: 1

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