CODEWITHSUNDEEP
linuxbashsedreplace
Justin
Justin

Reputation: 45320

Find and replace in bash

How can I write a simple find and replace inside of a bash script, but the replace comes from running a PHP script.

For example, I need to find: {{KEY}} and replace with the output of: php -f generate_key.php in the file app.config. Can sed accomplish this?

Upvotes: 1

Views: 280

Answers (3)

je4d
je4d

Reputation: 7838

I'd suggest something along these lines instead of the sed-based solutions above:

KEY="$(php -f generate_key.php)" awk '{gsub("{{KEY}}", ENVIRON["KEY"]);print;}' < app.config > app.config.new && \
mv app.config.new app.config

(Edited at T+20h to use ENVIRON instead of awk -v VAR=VAL due to the latter processing escape sequences in VAL)

Primarily because it performs the substitution without applying any interpretation or transformation to the output of your php script.

The sed-based solutions will fail if the output of your PHP script contains forward slashes, and they will also substitute various escaped characters (\ns, \ts etc) that are present in the output of your PHP script, which is probably not what you want.

Upvotes: 3

Olaf Dietsche
Olaf Dietsche

Reputation: 74008

Try this one

sed -e "s/{{KEY}}/`php -f generate_key.php`/g" app.config

This substitutes the replacement string with the output of the PHP script. If you want to modify app.config in place, add option -i to the command line

sed -i -e "s/{{KEY}}/`php -f generate_key.php`/g" app.config

As @je4d has observed, if the output of generate_key.php contains forward slashes /, you must use another delimiter instead, for example

sed -e "s;{{KEY}};`php -f generate_key.php`;g" app.config

Upvotes: 2

Diego Basch
Diego Basch

Reputation: 13059

try:

cat app.config|sed 's/{{KEY}}/something/g'

Upvotes: 0

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