CODEWITHSUNDEEP
c#.netreflection
snakile
snakile

Reputation: 54521

Objects representing certain types in C#

I would like to make assertions similar to the following:

aMethod.ReturnType == double
aString.GetType() == string

The above example clearly doesn't compile because double and string are not objects of type Type, they're not even legal C# expressions.

How do I express a Type of a certain C# type?

Upvotes: 2

Views: 97

Answers (3)

Ravi Y
Ravi Y

Reputation: 4376

Use typeof to get and compare types. 

aMethod.ReturnType == typeof(double)

aString.GetType() == typeof(string)

Upvotes: 6

Habib
Habib

Reputation: 223207

use is operator

Checks if an object is compatible with a given type.

bool result1 = aMethod.ReturnType is double;

bool result2 = aString is string;

Consider the following examples:

bool result1 = "test" is string;//returns true;
bool result2 = 2 is double; //returns false
bool result3 = 2d is double; // returns true;

EDIT: I missed that aMethod.ReturnType is a type not a value, so you are better of checking it using typeof

bool result1 = typeof(aMethod.ReturnType) == double;

Consider the following example. 

object d = 10d;
bool result4 = d.GetType() == typeof(double);// returns true

Upvotes: 2

Nicolas Voron
Nicolas Voron

Reputation: 2996

As other people said, use typeof(YourType), or the is operator (be carefull, is isn't a strict operator (think about inheritance) : for example, MyClass is object is true !)..

I don't know why you need aMethod.ReturnType, but it seems that you need generic parameters. Give it a try !

Upvotes: 0

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