CODEWITHSUNDEEP
javaarraysstring
Archie.bpgc
Archie.bpgc

Reputation: 24012

something like equalsIgnoreCase while using indexOf

I am using this code, to get the index of a String in an Array.

int n = Arrays.asList(Names).indexOf(textBox.getText());

The problem here is, if the String in textBox is different in case to its similar String in the Array. It returns -1. How can make it something like equalsIgnoreCase in case of String comparision.

Thank You

Upvotes: 5

Views: 6141

Answers (4)

Subhrajyoti Majumder
Subhrajyoti Majumder

Reputation: 41220

A different approach where internally make sure ignore case. 

public static int indexOfIgnoreCase(String[] strs, String text){

   int n = strs.length;
   for(int i=0;i<n;i++){
       if(strs[i].equalsIgnoreCase(text))
         return i;
   }
   return -1;
}
int n = indexOfIgnoreCase(Names,textBox.getText());

Upvotes: 1

Bhavik Shah
Bhavik Shah

Reputation: 5183

You can use StringUtils class of Apache commons libraries or this If you don't want to download the library look at the source code for logic to create the method. The stackoverflow link for using StringUtils

If you want to find the index of String from array of strings then there is another library ArrayUtils which has a method indexOf

here's the implementation of indexOf

 public static int indexOf(Object[] array, Object objectToFind, int startIndex) {
        if (array == null) {
            return INDEX_NOT_FOUND;
        }
        if (startIndex < 0) {
            startIndex = 0;
        }
        if (objectToFind == null) {
            for (int i = startIndex; i < array.length; i++) {
                if (array[i] == null) {
                    return i;
                }
            }
        } else {
            for (int i = startIndex; i < array.length; i++) {
                if (objectToFind.equals(array[i])) {
                    return i;
                }
            }
        }
        return INDEX_NOT_FOUND;
    }

since you can see that it uses .equals() I suggest you to

1) create a custom string class

2) add it to the array

3) override the .equals method like this

class StringCustom
{
String string;
//implement getters and setters
public String equals(Object o)
{
return this.getString().equalsIgnoreCase(((String)o).getString());
}
}

Upvotes: 3

SomeJavaGuy
SomeJavaGuy

Reputation: 7357

You can use the Collator class. in Here you can set different levels for your comparison. you can ignore lower and upper cases, and set some specific language charackters. In German for example it can set ß equal to ss.

here´s some documentary: Collator class

Edit : here´s an example Code for you

private int indexOf(String[] original, String search) {
    Collator collator = Collator.getInstance(); 
    collator.setStrength(Collator.SECONDARY);
    for(int i = 0;i<original.length;++i) {
        if(collator.equals(search, original[i]))
            return i;
    }
    return -1;
}

Upvotes: 3

Nikolay Kuznetsov
Nikolay Kuznetsov

Reputation: 9579

You can extend ArrayList in this way

    public class StringArrayList extends ArrayList<String> {
        @Override
        public boolean contains(Object o) {
            String paramStr = (String)o;
            for (String s : this) {
                if (paramStr.equalsIgnoreCase(s)) return true;
            }
            return false;
        }

        public int indexOf(Object o) {
            String paramStr = (String)o;
            int index = 0;
            for (String s : this) {
                if (paramStr.equalsIgnoreCase(s)) return index;
                index++;
            }
            return -1;
        }
    }

Eventually :

int n = new StringArrayList(Arrays.asList(Names)).indexOf(textBox.getText());

Upvotes: 0

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