CODEWITHSUNDEEP
c#
Ehsan
Ehsan

Reputation: 9

Access LSB of a byte and replace it with a value(1 or 0)

Here is the scenario, I have a list of numbers both positive and negatives. And another list of bits(0's and 1's). I have to replace these bits to the LSB's of every number in the 1st list (i.e:- of numbers).

for (int k = 0; k< 8; k++)
{
    i1 = index[k, 0];
    i2 = index[k, 1];
    string str1 = Convert.ToString(d[i1,i2], 2);
    str1 = str1.Substring(Math.Max(str1.Length - 8, 0)).PadLeft(8, '0');
    str1[0] = Tnbinary[k];
}

It won't allow me to modify str[0] - it says that it is only readable. What am I doing wrong and how can I modify my number?

Upvotes: 0

Views: 940

Answers (2)

Douglas
Douglas

Reputation: 54897

You could use bit operations:

byte b = -3;
byte b0 = (byte)(b & 254);   // Make LSB 0
byte b1 = (byte)(b | 1);     // Make LSB 1

If you're using signed bytes, just replace byte with sbyte.

Upvotes: 3

mvp
mvp

Reputation: 116367

If this is really a byte, why you don't do bit arithmetic, something like this:

new_byte = (old_byte & ~1) | new_bit

Upvotes: 1

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