CODEWITHSUNDEEP
c#asp.net-mvcasp.net-mvc-2
George Duckett
George Duckett

Reputation: 32448

How do I post an individual element of a model's collection to an action?

I have a model that contains a collection. I want to wrap each individual EditorFor in a form that posts to an action with a single element as the parameter. i.e:

class ModelWithCollection
{
    List<ElementModel> Elements { get; set; }
}

class ElementModel
{
    int Field { get; set; }
}

public ActionResult ElementAction(ElementModel viewModel)
{

}

However, my viewModel doesn't have the properties populated. I can understand this, as the editor renders the ids as things like Elements[0].Field. Rather where the action would like just Field.

How can I get around this?

I don't think I can manually build the post using jquery or something as it include uploading a file.

Upvotes: 2

Views: 46

Answers (2)

mipe34
mipe34

Reputation: 5666

You can workaround this using the partial view. If you move your EditorFor to partial view (with ElementModel as model) there won't be generated [0] brackets.

Upvotes: 1

moribvndvs
moribvndvs

Reputation: 42497

There is an overload of EditorFor that takes three arguments: expression, templateName, and htmlFieldName. If you supply the expression, null for templateName (thereby telling the helper to resolve the editor template the usual way), and an empty string for htmlFieldName, this should render the fields without the Elements[0]. prefix.

<%=Html.EditorFor(m => m.Elements[i], null, string.Empty)%>

Upvotes: 2

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