CODEWITHSUNDEEP
javabyte
Husky
Husky

Reputation: 1491

Reading two bytes from array of bytes

I am creating a simple aplication in Java, which allows me to read text file. I have a byte array which is wrapped into ByteBuffer:

 FileInputStream inputStream = new FileInputStream(name);
 FileChannel channel = inputStream.getChannel();
 byte[] bArray = new byte[8192];
 ByteBuffer byteBuffer = ByteBuffer.wrap(bArray);
 int read;

and then I use a while loop to go through the text file: 

while ( (read=channel.read(byteBuffer)) != -1 )
{
    for ( int i=0; i<read; i++ )
        //my code
    byteBuffer.clear( );
}

My question is how to read a Unicode character in this case. Unicode characters consist of 2 bytes (16 bits) so I suppose that bArray[i] holds first (higher) 8 bits and the subsequent 8 bits is the second part of this character. So for instance if I need to find out whether this character: "#" is currently on index i and i + 1, can I do it like this?? ("#" in binary representation: 0010 0011): 

if (bArray[i] == (byte)10 && bArray[i+1] == (byte) 11)

Thanks for responds

Upvotes: 3

Views: 1736

Answers (1)

Matt Ball
Matt Ball

Reputation: 359836

The simple answer is that you should not treat textual data as a stream of bytes. Specifically that means: don't use ByteBuffer.

Use an InputStreamReader, which knows how to interpret sequences of bytes using a given encoding.

Upvotes: 6

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