CODEWITHSUNDEEP
sqloracle-databasegroup-bysum
Romain Linsolas
Romain Linsolas

Reputation: 81607

Getting the sum of several columns from two tables

I want to get the sum of several columns from 2 different tables (these tables share the same structure).

If I only consider one table, I would write this kind of query:

SELECT MONTH_REF, SUM(amount1), SUM(amount2)
    FROM T_FOO
    WHERE seller = XXX
    GROUP BY MONTH_REF;

However, I would like to also work with the data from the table T_BAR, and then have a select query that return the following columns:

everything grouped by the value of MONTH_REF.

Note that a record for a given MONTH_REF can be found in one table but not in the other table. In this case, I would like to get the sum of T_FOO.amount1 + 0 (or 0 + T_BAR.amount1).

How can I write my SQL query to get this information?

For information, my database is Oracle 10g.

Upvotes: 11

Views: 61221

Answers (5)

sagar roy
sagar roy

Reputation: 1

SELECT (SELECT SUM(amount) from debit) as debitamounts, (SELECT SUM(amount) from credit) as creditamounts

Upvotes: -1

Kobi
Kobi

Reputation: 138007

You can union your tables before the group by (this is on Oracle, by the way):

SELECT t.month_ref, SUM(t.amount1), SUM(t.amount2)
  FROM (SELECT month_ref, amount1, amount2
          FROM T_FOO
         WHERE seller = XXX
         UNION ALL
        SELECT month_ref, amount1, amount2
          FROM T_BAR
         WHERE seller = XXX
         ) t
 GROUP BY t.month_ref

You may also union the tables with the seller field and filter by it later (in case you need more advanced logic):

 SELECT t.month_ref, SUM(t.amount1), SUM(t.amount2)
   FROM (SELECT month_ref, amount1, amount2, seller
           FROM T_FOO
          UNION ALL
         SELECT month_ref, amount1, amount2, seller
           FROM T_BAR) t
  where t.seller = XXX
  GROUP BY t.month_ref

Upvotes: 12

Lieven Keersmaekers
Lieven Keersmaekers

Reputation: 58431

Have you tried using a union?

SELECT MONTH_REF, SUM(amount1), SUM(amount2)
FROM (
  SELECT MONTH_REF, SUM(amount1) AS amount1, SUM(amount2) as amount2
      FROM T_FOO
      WHERE seller = XXX
      GROUP BY MONTH_REF
  UNION ALL SELECT MONTH_REF, SUM(amount1), SUM(amount2)
      FROM T_BAR
      WHERE seller = XXX
      GROUP BY MONTH_REF
  ) tmp
GROUP BY MONTH_REF

Upvotes: 2

Romain Linsolas
Romain Linsolas

Reputation: 81607

I finally get this working using the Lieven's answer.

Here is the correct code (amount1 = ... is not working on my environment, and there are too many ; in the query):

SELECT MONTH_REF, SUM(sumAmount1), SUM(sumAmount2)
FROM (
  SELECT MONTH_REF, SUM(amount1) as sumAmount1, SUM(amount2) as sumAmount1
      FROM T_FOO
      WHERE seller = XXX
      GROUP BY MONTH_REF
  UNION ALL SELECT MONTH_REF, SUM(amount1), SUM(amount2)
      FROM T_BAR
      WHERE seller = XXX
      GROUP BY MONTH_REF
  ) tmp
GROUP BY MONTH_REF

Upvotes: 1

Ruffles
Ruffles

Reputation: 79

Alternatively, an outer join should also work:

SELECT month_ref, 
       SUM(t_foo.amount1) + SUM(t_bar.amount1), 
       SUM(t_foo.amount2)+SUM(t_bar.amount2)
FROM   t_foo FULL OUTER JOIN t_bar
       ON t_foo.month_ref = t_bar.month_ref
GROUP BY month_ref

Upvotes: 1

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