CODEWITHSUNDEEP
fortran90gfortranfortran95
Kernel
Kernel

Reputation: 709

difference results between 10**-2 and E-2

The following program print 1 for 100E-2 and gives 0 for 100*10**(-2), that means that the operator exponent doesnot work for negative **, is that correct. Thanks in advance

program testme

implicit none

print*,100E-2

print*,100*10**(-2)

end program

Upvotes: 1

Views: 3259

Answers (1)

Jonathan Dursi
Jonathan Dursi

Reputation: 50937

You'll notice that the second print statement prints 0 -- no decimal pt, etc. Eg, integer zero. That's because 10 by itself is an integer literal, and raising that to the negative 2 power correctly gives zero; multiplying it by integer 100 still gives integer zero.

If you instead use

print*,100*10.**(-2)

you'll get the answer you expect.

The issue doesn't arise with 100e-2 because any number expressed with scientific notation is a floating point (real) literal.

Upvotes: 3

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