CODEWITHSUNDEEP
phpjquery
Jorge
Jorge

Reputation: 1

Passing variables through URL with JQuery

I have this but is not working which is a mixed of both answers found here (http://stackoverflow.com/questions/10369432/passing-link-with-parameters-with-jquery)... the alert message comes out empty and therefore the delete.php doesn't do anything

Any comments. I am using JQuery 1.8

<!DOCTYPE html>
<html>
<head>
<script src="http://code.jquery.com/jquery-latest.js"></script>
<script>
$(function(){

  $(".delete").click(function(e){
    var del_id = $(this).attr("id");
    e.preventDefault();
    $.post("../folder/delete.php", { iid: del_id } ,function(data){
    alert(data)
        //change the link to deleted
        $('#'+del_id).replaceWith('<a href="#" class="delete">Deleted</a>');


    });
  });
});

</script>
</head>
<body>
 <a class="delete" id="1" href='#'>Delete 1</a>
 <a class="delete" id="2" href='#'>Delete 2</a>
 <a class="delete" id="3" href='#'>Delete 3</a>
</body>
</html>

Delete.php is as follows:

<?php 
    extract($_POST); 
    extract($_GET); 
    if ($del_id!=0){ 
        require_once("../includes/include.php"); 
        deleteItem($del_id); 
    } 
?>

Upvotes: 0

Views: 185

Answers (1)

The Alpha
The Alpha

Reputation: 146269

You should change following line

if ($del_id!=0)

with this

if ($iid!=0)

because you are sending

{ iid: del_id } // iid is the variable

from the client side and $iid will be available in the $_POST so you can use without extracting the full $_POST array

if ($_POST['iid']!=0){...}

Also if you don't echo/print anything from the server side then you can't get back anything in the response.

Upvotes: 1

Related Questions