Reputation: 5
I'm new to Java and I'm trying to make a program that allows the user to input 100 numbers and if the user writes '0', then the program is suppose to print the smallest, largest, sum and all the numbers. I got all that to work but not to exit and print it all. My teacher said something about using a while loop, but how is that possible when you have a for loop?
Regards
public static void main(String[] args) {
int[] list = new int[100];
int min = 0;
int max = 0;
int sum = 0;
boolean first = true;
Scanner scan = new Scanner(System.in);
while(list[i] != 0) {
for (int i = 0; i < list.length; i++) {
System.out.print("Enter number (0 to exit) " + (1 + i) + ":");
list[i] = scan.nextInt();
}
for (int i = 0; i < list.length; i++) {
if (first == true) {
min = list[i];
first = false;
}
if (list[i] < min) {
min = list[i];
}
else if (list[i] > max) {
max = list[i];
}
sum = list[i] + sum;
}
if (list[i] == 0) {
System.out.print("Numbers are: " + list[0] + ", ");
for (int i = 1; i < list.length; i++)
System.out.print(list[i] + ", ");
System.out.println();
System.out.println("Smallest number is: " + min);
System.out.println("Largest numeber is: " + min);
System.out.println("Sum is: " + sum);
}
}
}
}
Upvotes: 0
Views: 7594
Reputation: 450
You only need one while loop to do this and additionally a for loop just to print the array if you want:
Scanner scan = new Scanner(System.in);
int i = 0;
int sum = 0;
int maxValue = Integer.MIN_VALUE;
int[] history = new int[100];
System.out.println("INPUT:");
int option = scan.nextInt();
while (option != 0 && i <= 100)
{
if (option > maxValue)
maxValue=option;
sum += option;
history[i] = option;
option = scan.nextInt();
i++;
}
System.out.println("OUTPUT: \n" + "SUM: " + sum + "\n MAX VALUE: " + maxValue);
for (int x : history)
System.out.print(x + "");
Upvotes: 2
Reputation: 22977
Here's the body of the method which will do what you've been asked. I have not used a while loop (but in fact, a for-loop is a kind of a while-loop internally).
int size = 100; // Set the number of numbers to input.
int[] list = new int[size]; // Create an array with 'size' elements.
int min = Integer.MAX_VALUE; // Set the highest possible integer as start value.
int max = 0; // Set the minimum to zero, assuming that the user won't input negative numbers.
int sum = 0; // Initialize the sum of the numbers in the list.
Scanner scan = new Scanner(System.in);
for (int i = 0; i < size; i++) { // Run 'size' times the process of inputting a number.
System.out.print("Enter number (0 to exit) " + (i + 1) + ": ");
int number = scan.nextInt();
if (number == 0) { // Quit program if input equals '0'
System.out.println("Exiting...");
break;
}
list[i] = number; // Add the current number to the list
sum += number; // Add the number to the total
if (number < min) { // If the number is smaller than the previous one, set this number as the smallest
min = number;
}
if (number > max) { // If the number is greater than the previous smallest number, set this number as the greatest
max = number;
}
}
// Output all numbers in the list
for (int i = 0; i < list.length; i++) {
if (list[i] != 0) {
System.out.print((i == 0 ? "" : ", ") + list[i]);
}
}
// You see the snippet (i == 0 ? "" : ", ")
// That is a shorthand if-else statement:
// If i equals 0, then "" (empty string), else ", " (comma and space).
// The statement
// System.out.print((i == 0 ? "" : ", ") + list[i])
// is the same as
// if (i == 0) {
// System.out.println("") + list[i];
// }
// else {
// System.out.println(", ") + list[i];
// }
System.out.println("Smallest number is: " + min);
System.out.println("Largest numeber is: " + max);
System.out.println("Sum is: " + sum);
Upvotes: 0
Reputation: 425013
You have muddled code. Better to use a pattern like this:
while (true) {
// read next
if (input == 0)
break;
}
Upvotes: 0