CODEWITHSUNDEEP
.netvb.netexecutable
Cyclone
Cyclone

Reputation: 18295

Managing .exe files

In VB.net, how can you programmatically launch a .exe file? Is there a way to check if the file is there?

I know there is some way to check using System.IO, but I have no idea. However, I have not even the slightest clue as to how to launch that .exe if it is there, so thanks for the help!

Upvotes: 2

Views: 297

Answers (4)

AAT
AAT

Reputation: 3386

You can use System.Diagnostics.Process to execute an .EXE, and can even capture the output if it is a console / command-line application. You would have something like this (but bear in mind this is simplified quite a bit!):

dim process as System.Diagnostics.Process
process.StartInfo.FileName = "program.exe"   ' You need to be smarter here!
process.StartInfo.Arguments = "whatever command line options you need"
process.Start()

To check if the program is still running you call

process.HasExited()

If you want to capture the output you need to set StartInfo.RedirectStandardOutput to True.

Upvotes: 1

Alfred Myers
Alfred Myers

Reputation: 6453

Use System.IO.File.Exists and System.Diagnostics.Process.Start.


        Dim someExe As String = "MyAppsPath\some.exe"
        Dim fullPath As String = Path.Combine(Environment.GetFolderPath(Environment.SpecialFolder.ProgramFiles), someExe)
        If File.Exists(fullPath) Then    'Checks for the existence of the file
            Process.Start(fullPath)      'Executes it
        End If

Upvotes: 2

Charlie Salts
Charlie Salts

Reputation: 13498

Check out the System.Diagnostics.Process class. There's a perfect code snippet on the MSDN page, so I won't duplicate it here.

The neat thing about Process is that you can actually launch a file (say, an HTML file) and it will open using the user's default browser. Many common programs accept command-line parameters as well - many browsers accept a URL as a command-line parameter so you can open a specific URL.

Upvotes: 2

Alin Popa
Alin Popa

Reputation: 211

http://msdn.microsoft.com/en-us/library/system.diagnostics.process.start.aspx

openFileDialog od = new OpenFileDialog(); string path = od.ToString() System.Diagnostics.Process.Start(path)

Upvotes: 1

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