CODEWITHSUNDEEP
java
srinath
srinath

Reputation: 2998

double returning only one precision in java

in my code i am performing division on numbers and storing it in a double variable. but the variable is returning with only one precision. i want to increase the precision how could i do that.

double x;
        for ( int i =0 ; i<10000 ; i++)
        {

            x= w[i] / l[i];
            System.out.println(x);
        }

in the above code w and l are integer arrays;

i am getting output like

3.0
0.0
1.0
0.0

i want to increase the precision upto 4 atleast.

Upvotes: 0

Views: 121

Answers (3)

JB Nizet
JB Nizet

Reputation: 691635

Use 

x = ((double) w[i]) / l[i];

As it is, you're dividing two integers using integer division, and assigning the resulting int to a double. Casting one of the operands to a double makes it do a double division instead.

Upvotes: 6

Joop Eggen
Joop Eggen

Reputation: 109547

System.out.printf("%10.4f", x);

Mind, only BigDecimal has precise precision. Doubles are approximations.

Upvotes: -1

Peter Lawrey
Peter Lawrey

Reputation: 533442

If you divide an int by another int you get an int not a double. Try

x = (double) w[i] / l[i];

Upvotes: 2

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