CODEWITHSUNDEEP
androidandroid-emulator
User13131313
User13131313

Reputation: 11

Android Program running in one machine not running in another

Can you please tell that this same program runs on one one machine and will not execute on another? It states null pointer exception on the other. When I click on CheckBox, it says unfortunately your activity has stopped.

Below is the code :-

package com.example.gtbactivity;

import android.app.Activity;
import android.os.Bundle;
import android.view.Menu;
import android.view.View;
import android.view.View.OnClickListener;
import android.widget.Button;
import android.widget.CheckBox;
import android.widget.CompoundButton;
import android.widget.CompoundButton.OnCheckedChangeListener;
import android.widget.TextView;

public class MainActivity extends Activity implements OnCheckedChangeListener, OnClickListener {

    CheckBox cb1,cb2;
    TextView t1,t2,t3;
    Button b;

    @Override
    protected void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.activity_main);
        cb1=(CheckBox)findViewById(R.id.checkBox1);
        cb2=(CheckBox)findViewById(R.id.checkBox2);
        b=(Button)findViewById(R.id.button1);   
        t1=(TextView)findViewById(R.id.textView1);
        t2=(TextView)findViewById(R.id.textView2);
        t3=(TextView)findViewById(R.id.textView3);


        b.setOnClickListener(this);
                cb1.setOnCheckedChangeListener(this);
                cb2.setOnCheckedChangeListener(this);


    }

    @Override
    public boolean onCreateOptionsMenu(Menu menu) {
        // Inflate the menu; this adds items to the action bar if it is present.
        getMenuInflater().inflate(R.menu.activity_main, menu);
        return true;
    }



    @Override
    public void onCheckedChanged(CompoundButton arg0, boolean arg1) {
         if(cb1.isChecked())
         { t1.setText("10");}
         else
         {t1.setText("0");}


         if(cb2.isChecked())
         { t2.setText("15");}
         else
         {t2.setText("0");}


    }
    @Override
    public void onClick(View arg0) {
        int total,a,b;
        a=Integer.parseInt(t1.getText().toString());
        b=Integer.parseInt(t2.getText().toString());

        total=a+b;
        t3.setText(String.valueOf(total));

    }

}

Upvotes: 0

Views: 53

Answers (1)

nandeesh
nandeesh

Reputation: 24820

I dont see textView t1 being initialized, maybe that is the reason you are getting nullpointer exception

Instead of 

    t2=(TextView)findViewById(R.id.textView1);

use 

    t1=(TextView)findViewById(R.id.textView1);

Upvotes: 2

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