CODEWITHSUNDEEP
pythonxml
Igal
Igal

Reputation: 4783

How to get inner element in xml file by using python

I have next xml :

<a>
  <aa id = 1>
    <data>aaaa</data>
  </aa>
  <aa id = 2>
    <data>bbbb</data>
  </aa>
  <aa id = 3>
    <data>cccc</data>
  </aa>
</a>

I would like to reach the data's text (aaaa,bbbb...) How can I do it ? (I've been using etree.ElementTree package)

Upvotes: 0

Views: 254

Answers (3)

RocketDonkey
RocketDonkey

Reputation: 37269

You could try this: 

In [1]: import xml.etree.ElementTree as ET

In [2]: tree = ET.parse('test.xml')

In [3]: root = tree.getroot()

In [4]: for el in root:
   ...:     print el.find('data').text
   ...:     
   ...:     
aaaa
bbbb
cccc

The only thing that you are missing from the code you provided is elem.find('data').text (inside of your for loop`) - that will return the value you are looking for.

Upvotes: 1

Igal
Igal

Reputation: 4783

tree = xml.parse(file) 
root = tree.getroot() 
listElem = root.findall("aa") 
for elem in listElem:
     tmp1 = elem.findall("data")
     str = tmp1[0].text

Upvotes: 0

Diego Navarro
Diego Navarro

Reputation: 9704

XML file:

<?xml version="1.0"?>
<a>
  <aa id="1">
    <data>aaaa</data>
   </aa>
   <aa id="2">
    <data>bbbb</data>
  </aa>
  <aa id="3">
    <data>cccc</data>
  </aa>
</a>

You can use an XPath query:

from lxml import etree

xml = etree.parse('/tmp/a.xml')

xml.xpath('.//data/text()')
['aaaa', 'bbbb', 'cccc'] #returns that

Upvotes: 1

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