Reputation: 5759
Is it possible to reference methods using function calls?
I thought I could try something like this:
function map(f,lst) {
// calling map method directly is fine.
return lst.map(f)
}
function mapm(m,lst) {
// where m is a passed method
return map( function(x) { return x.m() }, lst)
}
var list_a = [ [1,9],[2,8],[3,7],[4,6] ]
var list_b = mapm(pop,list_a)
>Uncaught ReferenceError: pop is not defined
Upvotes: 0
Views: 193
Reputation: 10734
You can use Function.prototype.call.bind
to create a functional version of a method. This is referred to as "uncurrying this
".
function map(f, lst) {
// calling map method directly is fine.
return lst.map(f)
}
function mapm(m,lst) {
// where m is a passed method
return map( function(x) { return m(x) }, lst)
}
var pop = Function.prototype.call.bind(Array.prototype.pop);
var list_a = [ [1,9],[2,8],[3,7],[4,6] ]
var list_b = mapm(pop, list_a)
If you need it to work in ancient browsers, you'll need to shim in bind
:
if (!Function.prototype.bind) {
Function.prototype.bind = function (oThis) {
if (typeof this !== "function") {
// closest thing possible to the ECMAScript 5 internal IsCallable function
throw new TypeError("Function.prototype.bind - what is trying to be bound is not callable");
}
var aArgs = Array.prototype.slice.call(arguments, 1),
fToBind = this,
fNOP = function () {},
fBound = function () {
return fToBind.apply(this instanceof fNOP && oThis
? this
: oThis,
aArgs.concat(Array.prototype.slice.call(arguments)));
};
fNOP.prototype = this.prototype;
fBound.prototype = new fNOP();
return fBound;
};
}
Upvotes: 1
Reputation:
Try:
mapm( 'pop', list_a )
...
return x[ m ]();
If you really want to reference the function itself:
mapm( list_a.pop, list_a ); // or Array.prototype.pop
...
return m.apply( x );
Upvotes: 4