CODEWITHSUNDEEP
phphtml
Alex
Alex

Reputation: 219

Form is not submitting php and html

everyone..

trying to submit a form.. and form and php code is in the same file index.php

if(isset($_POST['post_form'])) {
    echo "ISSET";

    $post_sender=$id;
    $post_reciever=$id2;
    $post_cont=$_POST['news_text'];
    $post_cont=htmlentities($post_cont);
    $post_cont=mysql_real_escape_string($post_cont);

    $post_sql=mysql_query("INSERT INTO wall_posts (from, to, content, date) VALUES ('$post_sender','$post_reciever','$post_cont',now())") or die(mysql_error());

    }else{
        echo "NOT SET";
    }

html form

<form  method='POST' action='index.php' enctype='multipart/form-data' id='news_form' name='post_form' >
<textarea id='news_text' name='news_text' >type here..........</textarea>

<input type='submit' id='wall_post_btn' name='wall_post_btn' value='submit'>

</form>

where is my mistake..???

there is no mistake in the code..the file itself is corrupted..just made a test in a new PHP file...works just fine...thanks guys..

Upvotes: 0

Views: 98

Answers (6)

Morten Repsdorph Husfeldt
Morten Repsdorph Husfeldt

Reputation: 1003

There are two problems:

  1. You need to connect to your mysql server to use mysql_real_...
  2. mysql_real_... is deprecated and is being removed from php

Take a look here for alternatives: http://php.net/manual/en/function.mysql-real-escape-string.php

Upvotes: 0

Habid Pk
Habid Pk

Reputation: 218

Use this code its working fine

<?php
if($_SERVER['REQUEST_METHOD']=="POST") {
   echo "ISSET";
    $post_sender=$id;
    $post_reciever=$id2;
    $post_cont=$_POST['news_text'];
    $post_cont=htmlentities($post_cont);
    $post_cont=mysql_real_escape_string($post_cont);

    $post_sql=mysql_query("INSERT INTO wall_posts (from, to, content, date) VALUES ('$post_sender','$post_reciever','$post_cont',now())") or die(mysql_error());

    }else{
        echo "NOT SET";
    }
?>
<form  method='post' action='index.php' enctype='multipart/form-data' id='news_form' name='post_form' >
<textarea id='news_text' name='news_text' >type here..........</textarea>

<input type='submit' id='wall_post_btn' name='wall_post_btn' value='submit'>

</form>

Upvotes: 0

Bhavik Shah
Bhavik Shah

Reputation: 2291

post_form is the name of form. You must check for the submit button, wall_post_btn.

if(isset($_POST['wall_post_btn'])) {
  // entire code here
}

Upvotes: 2

shadyyx
shadyyx

Reputation: 16055

The problem is You are checking the name of the form present in the $_POST, which is never present...

What You should test is the name of the submit button, e.g.:

if(isset($_POST['wall_post_btn'])) {

Next You could use one line for sanitizing the input:

$post_cont= mysql_real_escape_string(htmlentities($_POST['news_text']));

And last one: start using PDO with prepared statements or at least mysqli_* functions as mysql_* ones are deprecated now...

Upvotes: 0

ROY Finley
ROY Finley

Reputation: 1416

You should not use mysql as it has been depreciated. look into mysqli or PDO

This:

"INSERT INTO wall_posts (from, to, content, date) VALUES ('$post_sender','$post_reciever','$post_cont',now())"

should be:

"INSERT INTO wall_posts (from, to, content, date) VALUES ('".$post_sender."','".$post_reciever."','".$post_cont."',now())"

Upvotes: 0

ashley
ashley

Reputation: 2767

$_POST['wall_post_btn']. the name of the submit, not the form

Upvotes: 1

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