Reputation:
I need to generate a random number from the following data:
0-10 : 23%
10-80 : 50%
80-100 : 27%
How do I generate a random number from such information?
One way would be to fit a distribution but I have to do this for about hundred variables and I don't want to fit 100 distributions. Any hints?
import random
a=[23, 73, 100]
b=[10, 80, 100]
rndval=awesomefunction(a,b)
Now, regarding awesomefunction()
, I have absolutely no clue.
But, from what little I know, (and a very sloppy implementation)
temp_rand=random.uniform(0,100)
if(temp_rand<=23):
rndval=random.uniform(0,10)
if(temp_rand<=73 && temp_rand>23):
rndval=random.uniform(10,80)
if(temp_rand>73):
rndval=random.uniform(80,100)
But IMHO, this is sloppy beyond measure.
Upvotes: 2
Views: 1595
Reputation: 81509
C# implementation of a "ranging" random number generator with N ranges possible.
using System;
using System.Collections.Generic;
public class MyClass
{
static void Main()
{
var ranges = new List<Range>
{
new Range( 0, 23, 0, 10),
new Range(24, 73, 11, 80),
new Range(74, 100, 81, 100),
};
for (var i = 0; i < 50; i++)
{
var randInt = GetRand(0, 100, ranges);
Console.WriteLine(randInt);
}
Console.ReadKey();
}
static Random _myRandom = new Random();
static int GetRand(int absMin, int absMax, List<Range> ranges)
{
var i = _myRandom.Next(absMin, absMax);
foreach (var range in ranges)
{
if (i >= range.PercentMin && i <= range.PercentMax)
{
return _myRandom.Next(range.ValueMin, range.ValueMax);
}
}
throw new ArgumentOutOfRangeException("Incomplete range?");
}
}
class Range
{
public int PercentMin { get; set; }
public int PercentMax { get; set; }
public int ValueMin { get; set; }
public int ValueMax { get; set; }
public Range(int pctMin, int pctMax, int min, int max)
{
PercentMin = pctMin;
PercentMax = pctMax;
ValueMin = min;
ValueMax = max;
}
}
Upvotes: 0
Reputation: 2790
See http://www.keithschwarz.com/darts-dice-coins/ and Data structure for loaded dice? for information about several approaches, trading speed and complexity.
Upvotes: 1
Reputation: 81509
You could do a two-step random fetch. The first random number would tell you which quartile (roughly) to use. Then randomly pull from that group.
Pseudocode:
randPercentile = 100 * Rand()
if (randPercentile <= 23)
randResult = Rand(0, 23)
else if (randPercentile > 23 && randPercentile <= 73)
randResult = Rand(24, 73)
else
randResult = Rand(74, 100)
print randResult
You have to check the Rand API for your language/framework of choice but most Rand functions will return a float between 0 and 1 by default with overloads for minimum/maximum value ranges. And the latter call (with min/max) can be coded by you pretty easily if it's not available.
Upvotes: 0
Reputation: 813
You can have 2 random generators to achieve this. The first should generate a random double from 0 to 1.
For this generator, you should check to see if the random number is from 0 to .22, .23 to .73, or .74 to 1. If the number falls within the first range, you just run another random number generator that generates a number from 0 to 10, and that's your number. The same goes for the second and third ranges.
Some high level pseudocode:
double firstRandomNumber = generateRandomNumberFromZeroToOne();
if (firstRandomNumber <= .22) {
//generate random number from 0 to 10 and that's your number.
} else if (firstRandomNumber <= .73) {
//generate random number from 10 to 80 and that's your number.
} else {
//generate random number from 80 to 100 and that's your number.
}
A side note: Most languages already have random number generators that will generate a random number from 0 to 1 or an integer up to a specific range (0 to 10).
Upvotes: 2