CODEWITHSUNDEEP
phprelative-path
mauriblint
mauriblint

Reputation: 1707

PHP Project relative paths and urls

I'm working on a project. It's a control panel to manage a website. The folder structure is like this:

I set some settings in my config file, some of those are:

$site_url = $_SERVER['SERVER_NAME'];
define ('ABSPATH', 'http://'.$site_url.'/cpanel');

So, my question is: How can I load all resources (images, css, js) relative to the ABSPATH constant, and all <a> tags?

With this, I could move the "cpanel project" to an other directory level and it would still work. Like a Wordpress Blog, only setting the Blog URL..

Upvotes: 1

Views: 1199

Answers (4)

Zamicol
Zamicol

Reputation: 5024

Here is an alternative based on Mike Brant's solution.

//APP_ROOT and APP_BASE assumes that the current location of this 
//script is located in the root of your application.  
//Also assumes that the HOST_NAME is what you want in the URL.  
//See https://php.net/manual/en/reserved.variables.server.php for reference 
define('HOST_NAME', $_SERVER['HTTP_HOST']);
(empty($_SERVER['HTTPS'])) ? define('PROTOCOL', 'http') : define('PROTOCOL', 'https');
define('WEB_SERVER_ROOT', $_SERVER['DOCUMENT_ROOT']);
define('APP_ROOT', __DIR__);
$appBase = str_replace(pathinfo(__FILE__, PATHINFO_BASENAME), '', $_SERVER['SCRIPT_NAME']);
define('URL_BASE', PROTOCOL . '://' . HOST_NAME . $appBase);

Upvotes: 0

Mike Brant
Mike Brant

Reputation: 71384

You are probably best served defining several different variables, as having a URL is not going to be useful for purposes of includes and such. You can do something like this:

DEFINE(HOST_NAME, $_SERVER['SERVER_NAME']);
DEFINE(WEB_SERVER_ROOT, $_SERVER['DOCUMENT_ROOT']);
DEFINE(APP_ROOT, __DIR__);
DEFINE(URI_BASE, str_replace(WEB_SERVER_ROOT, '', APP_ROOT);
if ($_SERVER['HTTPS'] == 'on') {
    DEFINE(PROTOCOL, 'http');
} else {
    DEFINE(PROTOCOL, 'https');
}
DEFINE(URL_BASE, PROTOCOL . '://' . URI_BASE);

For includes you could then do something like:

include(APP_ROOT . '/modules/somefile.php');

For outputting image, javascript, css, etc. links you could use something like:

<img src="<?php echo URL_BASE; ?>/images/someimage.jpg" />
<a href="<?php echo URL_BASE; ?>/somepage">Some Page</a>
<script type="text/javascript" src="<?php echo URL_BASE; ?>/js/somejs.js" />

Upvotes: 2

Mickle Foretic
Mickle Foretic

Reputation: 1409

There are several ways to do what you are saying, but one of the most simple one is to use the BASE tag.

<head>
<base href="http://www.yoursitewithimages.com/folder-with-files/" target="_blank">
</head>

Then you can just use

<img src="img/image.jpg">

and it will be read as

<img src="http://www.yoursitewithimages.com/folder-with-files/img/image.jpg">

More info here http://www.w3schools.com/tags/tag_base.asp or here http://www.w3.org/TR/html-markup/base.html

Upvotes: 1

swatkins
swatkins

Reputation: 13630

Wouldn't you just do something like this in your php view?

<script type="text/javascript" src="<?= ABSPATH ?>/my_js_file.js"></script>
<link rel="stylesheet" type="text/css" href="<?= ABSPATH ?>/my_css_file.css">

<img src="<?= ABSPATH ?>/my_image_file.jpg" />

This way, you could move the directory anywhere within your docroot and just change the value of ABSPATH in your config file.

Upvotes: 3

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