CODEWITHSUNDEEP
pythondictionarypython-2.7
PKR
PKR

Reputation: 187

How to convert a list into a required dictionary format

Input is given as a = "test1,test2,test3,test4,...etc"

I want the output like below:

b={"test1":"test1","test2":"test2","test3":"test3",..etc}

Please let me know how can I do this.

Upvotes: 1

Views: 106

Answers (3)

Neil
Neil

Reputation: 489

Another way:

tmp = a.split(",")
b = dict(zip(tmp,tmp))

Upvotes: 0

Martijn Pieters
Martijn Pieters

Reputation: 1121724

To create a dictionary in a loop, use a dict comprehension.

Assuming that your a variable is a string with comma-separated values, the following would work:

{v: v for v in a.split(',')}

where we use each value in the comma-separated list as both key and value for the resulting dictionary.

The {k: v ...} dict comprehension was added in Python 2.7 and 3.0, in earlier python versions generate 2-value tuples instead:

dict((v, v) for v in a.split(','))

Upvotes: 6

pemistahl
pemistahl

Reputation: 9584

An addition to Martijn Pieters' correct answer:

The dict comprehension only works with Python versions >= 2.7. For earlier versions of Python, you can create 2-valued tuples and pass them to the dict() function:

dict((item, item) for item in a.split(','))

And, finally, to mention this option as well, this would be the long way:

d = {} # alternatively, d = dict()
for item in a.split(','):
    d[item] = item

Upvotes: 2

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