Reputation: 2860
How can I create a regex expression that will match only letters with numbers?
I've tried something like (?>[A-z]+)([a-z0-9]+)
.
The regex should give the following result:
1234b --> true
1234 --> false
abcd --> false
abcd4 --> true
12b34 --> true
Upvotes: 13
Views: 17105
Reputation: 93636
Don't make it be one regex if you don't have to. Use two regexes that both have to match. In Perl, it would be like this
if ( /[a-zA-Z]/ && /\d/ )
Upvotes: 0
Reputation: 1331
^([a-Z]+[0-9]+|[0-9]+[a-Z]+)[a-Z0-9]*$
and a simpler version inspired by TimPietzcker:
^([a-Z]+[0-9]|[0-9]+[a-Z])[a-Z0-9]*$
Upvotes: 1
Reputation: 3693
(?:\d+[a-z]|[a-z]+\d)[a-z\d]*
Basically, where 1 and a are any number and any letter, it matches 1a or a1, surrounded by any number of alphanumeric characters.
edit: shorter and probably faster now
Upvotes: 14
Reputation: 3956
Other answers are incorrect, and will allow any string that only contains letters, numbers or both. My expression will specifically exclude strings that consist only of letters or only of numbers.
[A-Za-z0-9]*([a-zA-Z]+[0-9]+|[0-9]+[a-zA-Z]+)
Any number of letters and numbers, followed by at least one letter followed by a number or at least one number followed by a letter.
There is possibly a simpler way of doing this, however. Mine seems long winded. Maybe it's not. Anyone care to pitch in? :P
Upvotes: 6