CODEWITHSUNDEEP
phpnavigationdirectory
Brandon Williams
Brandon Williams

Reputation: 79

PHP - Listed directory files as navigation. How to display index first and display as 1?

I am building a page navigation based on php files in a directory.

At the moment I have 5 files in my directory: index.php, 2.php, 3.php, 4.php, 5.php

With my limited PHP skills I have managed to work the code to display the navigation as: [2] [3] [4] [5] [index]

However I have hit a road block that is a little beyond me at this time.

I would like to have [index] displayed as [1], and I would like [1] to be displayed first.

I would like to have it look like this: [1] [2] [3] [4] [5]

<?php
    $pathfiles = "../directory/";
    $files = glob("../directory/*.php");
    foreach( $files as $file ) {
        echo '[<a href="'.($pathfiles).''
        .basename($file).'">'
        .basename($file, ".php").'</a>] ';
    }
?>

Any help or leads would be appreciated. Thank you in advance for your time.

Upvotes: 1

Views: 287

Answers (2)

Daniel
Daniel

Reputation: 3806

You'll need to push the index.php value to the top before iterating;

$key = array_search('index.php', $files);
unset($files[$key]);
natsort($files);
array_unshift($files, 'index.php');

Then, in your iteration, just look for the value index.php and change it to [1]

Upvotes: 1

Flolink
Flolink

Reputation: 39

<?php
$pathfiles = "../directory/";
$files = glob("../directory/*.php");
$list = array();
    foreach($files as $file)
    {
        $nb = basename($file) == "index" ? "1" : basename($file);
        $list[$nb] = '[<a href="'.($pathfiles).''.basename($file).'">'.$nb.'</a>] ';
    }
    ksort($list);
    foreach ($list as $l)
    {
        echo $l;
    }
?>

Upvotes: 1

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