Reputation: 702
I am using Json.NET to create a definition of json whose structure may change. I am therefore unable to simply serialize a class and am creating the structure on the fly using Json to Linq. I am having issues creating the following structure using JObject, JArray, JProperty, etc
{
'external_id':'UNIQUE_ID_222222222',
'firstname':'John',
'lastname':'Smith',
'customFields':
{
'custom1':'custom1 val',
'custom2':'custom2 val',
'custom3"':'custom3 val'
}
}
I tried using the following code:
Dim json As New JArray()
Dim jsonObj As New JObject( _
New JProperty("external_id", "UNIQUE_ID_222222222"),
New JProperty("firstname", "John"),
New JProperty("lastname", "Smith"))
Dim jsonCustomFields As New JArray
Dim jsonCustomObject As New JObject
jsonCustomFields.Add(jsonCustomObject)
For Each field In CustomFieldList
jsonCustomObject.Add(New JProperty(field.Label, field.Value))
Next
jsonObj.Add(New JProperty("customFields", jsonCustomFields))
json.Add(jsonContrib)
However when I do this I get a different pattern that was not accepted by the webservice
{[
{
"external_id": "50702",
"firstname": "John",
"lastname": "Smithson",
"customFields": [
{
"custom1":"custom1 val",
"custom2":"custom2 val",
"custom3":"custom3 val"
}
]
}
]}
I thought that I should be adding properties directly to the JArray but doing this causes a run time exception.
I have seen a similar pattern that is created when you deserialize a Dictionary(String, String) object but I don't really want to add my custom fields to a dictionary only to then deserialize them. It must be possible to create them using the above notation.
Upvotes: 5
Views: 1789
Reputation: 1010
You do not need a JArray
, instead use JObject
Following code is C# but you will be able to figure out
JObject jObject = new JObject();
jObject.Add(new JProperty("external_id", "UNIQUE_ID_222222222"));
jObject.Add(new JProperty( "firstname", "John" ));
jObject.Add(new JProperty( "lastname", "Smith" ));
JObject customFields = new JObject();
//Your loop
customFields.Add( "custom1", "custom1 val" );
customFields.Add( "custom2", "custom2 val" );
customFields.Add( "custom3", "custom3 val" );
jObject.Add( new JProperty( "customFields", customFields ) );
Let me know this works or not
Upvotes: 4