Reputation: 12229
How would I select all the children in a table except for the first and last? I've tried this, but it ends up selecting all children that aren't first and all children that aren't last, which ends up being all children:
table.programs tr td:not(:first-child), table.programs tr td:not(:last-child) {
}
I want all children that are neither first nor last. How can I do this?
Upvotes: 69
Views: 54298
Reputation: 69
like this.
li:nth-child(n+2):nth-last-child(n+2) { background: red; }
for your requirement
table.programs tr td:nth-child(n+2):nth-last-child(n+2) { /* Your Style */ }
Upvotes: 4
Reputation: 173
It works in this way
table.programs tr td:nth-child(1n+2):not(:last-child)
Upvotes: 1
Reputation: 201508
Use two :not()
selectors combined, thereby referring to elements that match both of them, i.e. to elements that match neither of the selectors used as operands of :not()
:
table.programs td:not(:first-child):not(:last-child)
Upvotes: 116
Reputation: 21262
The jQuery solution is fine, but if you want to do it in pure CSS I'd suggest you to apply the rules to the whole table and then reset them for the first and last children. i.e:
table.programs tr td {
/* your rules here */
}
table.programs tr:first-child td:first-child,
table.programs tr:last-child td:last-child {
/* reset your rules here */
}
Upvotes: 6
Reputation: 7740
I think this should work for you:
table.programs tr td:not(:first-child,:last-child)
Upvotes: 2