CODEWITHSUNDEEP
phpformattingdecimal
dotty
dotty

Reputation: 41433

Print numeric values to two decimal places

I'm using a simple loop to echo back some numbers.

<?php
$inc = 0.25;
$start =  0.25;
$stop = 5.00;
?>
        
<?php while($start != ($stop + $inc)){ ?>
<option><?php echo $start ?></option>
<?php $start = $start + $inc; ?>
<?php } ?>

However 5.00 appears as 5 and 4.50 appears as 4.5.

How would I get this script to display 5.00, 4.00, 3.00, 3.50?

Upvotes: 0

Views: 3297

Answers (5)

martin.malek
martin.malek

Reputation: 2218

use this:

printf("%01.2f", $start)

or if you need to store it to variable

$var = sprintf("%01.2f", $start)

You can also use number_format, this is good when you need to format that in some country formatting rules. You can provide decimal and thousand separator

number_format($start, 2)

Upvotes: 7

Pellumb
Pellumb

Reputation: 1

$price1 = 6.67; $price2 = 5.55; $total = $price1 + $price2;
echo $total;
echo "\n";
//the . means dot position, 4 means 4 digits after the .
$result= sprint("%0.4f", $total); 
echo $result;
outputs: 12.22 12.2200

f means float (maybe obvious maybe not:) can try above code by changing the number after the . to get whatever number of digits you want.

Upvotes: 0

Ian
Ian

Reputation: 4258

You'll want to use printf() for formatted strings: 

printf("%01.2f", $start)

The full manual for (s)printf can be found here

Upvotes: 2

KiNgMaR
KiNgMaR

Reputation: 1567

There also is number_format that lets you choose the thousand and decimal separators: http://de.php.net/manual/en/function.number-format.php

Upvotes: 4

w35l3y
w35l3y

Reputation: 8773

<?php while($start != ($stop + $inc)){ ?>
<option><?php printf('%01.2f', $start) ?></option>
<?php $start = $start + $inc; ?>
<?php } ?>

Upvotes: 1

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