CODEWITHSUNDEEP
assemblyx86dos
Belbesy
Belbesy

Reputation: 117

x86 iterate over a 2-byte word array

I'm writing a loop in an 8086 game using emu8086 and I want to iterate over word values but not bytes of an array declared like this;

player_fire  dw 320 dup(0)

; ...

mov  bx, offset player_fire
mov  cx, 320
fire_loop:
mov  ax, [bx+si]
inc  si
loop fire_loop

but I know that this is wrong. I also have problems writing to the ith element whether I should reference it with bx + si or bx + (2*si) ?

Upvotes: 1

Views: 2076

Answers (2)

Mohammad Dwekat
Mohammad Dwekat

Reputation: 3

 fire_loop:
  mov ax,[bx+si];;mov to the next sell and put in ax
  add si, 2; inc si
  loop fire_loop;dex cx and loop

Upvotes: 0

Aki Suihkonen
Aki Suihkonen

Reputation: 20037

The ith element is located at [base + 2*register].

That can't however be written directly before 80386 addressing modes. On 8086+ you can do it with:

 fire_loop:
  mov ax,[bx+si]
  add si, 2
  loop fire_loop

Upvotes: 3

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