CODEWITHSUNDEEP
jqueryslideshowfadein
MultiformeIngegno
MultiformeIngegno

Reputation: 7059

Simple jQuery Slideshow with fadein/fadeout

I have this really simple jQuery Slideshow: http://jsfiddle.net/6zA4B/

HTML:

<div class="fadein">
<img src="http://farm3.static.flickr.com/2610/4148988872_990b6da667.jpg">
<img src="http://farm3.static.flickr.com/2597/4121218611_040cd7b3f2.jpg">
<img src="http://farm3.static.flickr.com/2531/4121218751_ac8bf49d5d.jpg">
</div>

JavaScript:

​$(function(){
    $('.fadein img:gt(0)').hide();
    setInterval(function(){$('.fadein :first-child').fadeOut().next('img').fadeIn().end().appendTo('.fadein');}, 3000);
});​

It works perfectly, I just want to replace the 3 img tags with 3 divs (so I can include a caption below the images). How can I modify the script to achieve that? I tried with this but probably I'm doing something wrong...

HTML:

<div class="fadein">
    <p><img src="http://farm3.static.flickr.com/2610/4148988872_990b6da667.jpg">image1</p>
    <p><img src="http://farm3.static.flickr.com/2597/4121218611_040cd7b3f2.jpg">image2</p>
    <p><img src="http://farm3.static.flickr.com/2531/4121218751_ac8bf49d5d.jpg">image3</p>
</div>

JavaScript:

$(function(){
    $('.fadein p:gt(0)').hide();
    setInterval(function(){$('.fadein :first-child').fadeOut().next('p').fadeIn().end().appendTo('.fadein');}, 3000);
});​

http://jsfiddle.net/S4SmM/1/ :D

Upvotes: 3

Views: 33227

Answers (5)

Ashirbad Ray
Ashirbad Ray

Reputation: 1

<!doctype html>
<html lang="en">
<head>
  <meta charset="utf-8">
  <title>add demo</title>
  <style>
    .slider{
       position: relative;
       width: 1000px;
       height: 300px;
       margin: 0px auto;
    }

    img {
       position: absolute;
       top:0;
       left:0;
       width: 1000px;
       height: 300px;
    }
</style>
  <script src="https://code.jquery.com/jquery-3.5.0.js"></script>
 
    <script>
        $( document ).ready(function(){
    fade();
    setInterval(fade, 5000);
});
var i = 1;
function fade() {
  $('#img-' + i).fadeOut(2000);
  i++;
  if (i>3){
        i = 1
      }
    
  $('#img-' + i).fadeIn(2000);

}  </script>
</head>
<body>
    <div class="slider">
        <img id="img-1" src="https://i.picsum.photos/id/1028/1921/1480.jpg?hmac=7rV8P9L5kV_5PMZcIIXOT-wN3gn7VwoYLl5YC4uNr0g">
        <img id="img-2" src="https://i.picsum.photos/id/455/1922/1480.jpg?hmac=vqLUitWLN713y2jRmGcpEAChI9qUH5q7HB1yLjPNjYU">
        <img id="img-3" src="https://i.picsum.photos/id/798/1920/1480.jpg?hmac=9yv1GtCO1YXMiM0ShMmoT-LJn0ZrV6A7a_aY0VWWqr8">
     </div>

</body>
</html>

Upvotes: 0

Rohit
Rohit

Reputation: 5721

You can also use a plugin jquery-fade-slider

$(selector).fadeSlider()

Link to Github Repo

Upvotes: 0

SiteKickr
SiteKickr

Reputation: 249

I like Andrew Whittaker's answer, but prefer to use the Fadeout callback to give it a little more "animation":

setInterval(function(){$('.fadein > :first-child').fadeOut(1000, function() {
    $(this).next('p').fadeIn(1000).end().appendTo('.fadein');   
})
}, 5000);

Upvotes: 0

extramaster
extramaster

Reputation: 2655

Use the following code:

HTML:

<div class="fadein">
    <div><img src="http://farm3.static.flickr.com/2610/4148988872_990b6da667.jpg"><p>image1</p></div>
<div><img src="http://farm3.static.flickr.com/2597/4121218611_040cd7b3f2.jpg"><p>image2</p></div>
    <div><img src="http://farm3.static.flickr.com/2531/4121218751_ac8bf49d5d.jpg"><p>image3</p></div>
</div>
​

CSS:

.fadein { position:relative; height:332px; width:500px; }
.fadein div {position:absolute;text-align:center;height:100%;}
.fadein p { position:absolute; bottom:0;width:100%;color:white;background-color:rgba(0,0,0,0.6);height:1em;padding-bottom:10px;}​

JS:

$.fn.nextOrFirst = function(selector) {
    var next = this.next(selector);
    return (next.length) ? next : this.prevAll(selector).last();
}

$(function() {
    $('.fadein div:eq(0)').addClass("active");
    $('.fadein div:gt(0)').hide();
    setInterval(function() {
        $('.active:eq(0)').fadeOut().removeClass("active").nextOrFirst('div').addClass("active").fadeIn().end()
    }, 3000);
});​

JsFiddle: http://jsfiddle.net/S4SmM/5/

Upvotes: 4

Andrew Whitaker
Andrew Whitaker

Reputation: 126042

One of your selectors is slightly off:

$('.fadein :first-child')

Is selecting all elements that are first children underneath .fadein. This includes the first child of the p elements, which are the images you're trying to rotate to.

You want to restrict the :first-child selector to elements directly under .fadein. One way would be to use the child selector:

$('.fadein > :first-child')

Example: http://jsfiddle.net/S4SmM/4/

Upvotes: 8

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