CODEWITHSUNDEEP
java
edinvnode
edinvnode

Reputation: 3557

Java split text by lines (other solutions didn't work)

I am writing code to split lines in java but it doesn't work properly.

import java.io.FileNotFoundException;
import java.io.IOException;
import java.util.ArrayList;
import java.lang.*;

public class mainprogram {
    public static void main(String [] args ) throws FileNotFoundException, IOException
    {
    //creating object for purpose of writing into file
    writFile ObjectwritFile = new writFile();

    //creating object for purpose of reading from file
    loadFile ObjectloadFile = new loadFile();

    //this will be used for storing text into from file
    String text="";

    //text = ObjectloadFile.loadFile("C://names.txt");

    System.out.println(text);

    ObjectwritFile.writeFile("C://testfile.txt",text);

   //these regexp didn't work
    //String regexp = "[\\r\\n]+"; 
   //String regexp = "[\\s,;\\n\\t]+";  

  String regexp = "[\\n]+";

   //this one didn't work  
   //String[] lines = text.split(regexp);



    String[] lines = text.split(System.getProperty("line.separator"));

    for(int i=0; i<lines.length; i++){

    System.out.println("Line "+i+": "+lines[i]);
    ObjectwritFile.writeFile("C://testfilelines.txt","Line "+i+": "+lines[i]);

    }         
          }

    }

The text is in this format.

John, Smith, 4 ,5 ,6
Adams, Olsen, 7,8, 3
Steve, Tomphson , 4,5 9
Jake, Oliver, 9,8,9

Once I separate text by lines I have to sort it by alphabet and but numbers into a file with same text format.

Upvotes: 2

Views: 4079

Answers (5)

Bohemian
Bohemian

Reputation: 425348

Try this:

String[] lines = text.split("\n+");

Note that "\n" is not a special regex character, so it doesn't need escaping. The regex "\\n" (in java) is the literal "n"

Upvotes: 2

Ryan Stewart
Ryan Stewart

Reputation: 128919

I don't fully understand what you're trying to do, but if your input text is consistently in the format: String,String,int,int,int, then this groovy code will read the lines, sort them by the final three numbers in ascending order, and print them out:

def lines = new File('textSort.txt').readLines()
lines.sort{ it.split(',')[4].trim() }
lines.sort{ it.split(',')[3].trim() }
lines.sort{ it.split(',')[2].trim() }
println lines.join('\n')

It's a little hacky sorting three times, but it gets the job done and will work fine unless you have a large dataset. The Java code for it would be correspondingly much larger.

Upvotes: 1

s.d
s.d

Reputation: 29436

You can use Scanner with \n as delimiter, to read line by line.

Upvotes: 3

mindas
mindas

Reputation: 26733

Why bother doing everything by hand? Just use one of the available CSV libraries, such as Super CSV.

Upvotes: 1

PermGenError
PermGenError

Reputation: 46428

String regexp = "[\\n]+";

   //this one didn't work  
   //String[] lines = text.split(regexp);

you don't need to escape \n with an extra backslash \\n as \n is a valid escape sequence.

String regexp ="[\n]+"; //will work fine

Upvotes: 0

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