CODEWITHSUNDEEP
jsonjacksondouble-quotes
Freewind
Freewind

Reputation: 198238

How to let jackson generate json string using single quote or no quotes?

For example, I want to generate a json string for ng-style:

<th ng-style="{width:247}" data-field="code">Code</th>

But with jackson, the result is:

<th ng-style="{&quot;width&quot;:247}" data-field="code">Code</th>

It's not easy to read.

So I want jackson to generate the json string with single quote or no quotes. Is it possible to do this?

Upvotes: 20

Views: 27418

Answers (3)

Remigius Stalder
Remigius Stalder

Reputation: 2170

JsonGenerator.Feature.QUOTE_FIELD_NAMES

is deprecated, you can use this instead:

mapper.configure(JsonWriteFeature.QUOTE_FIELD_NAMES.mappedFeature(), false);
mapper.configure(JsonReadFeature.ALLOW_UNQUOTED_FIELD_NAMES.mappedFeature(), true);

Note that JsonParser.Feature.ALLOW_UNQUOTED_FIELD_NAMES is not deprecated (as of now), the corresponding JsonReadFeature is mentioned here just for completeness.

Upvotes: 5

Deepak
Deepak

Reputation: 1

The simplest and the best option is to use regular expression and update the string value.

The sample code is as listed below.

partNumberList=partNumberList.replaceAll(":", ":\"").replaceAll("}", "\"}");

The complete code is as shown below

public static void main(String[] args) throws JsonParseException, JsonMappingException, 
    IOException {
    TestJack obj = new TestJack();
    //var jsonString ='{"it":"Stati Uniti d'America"}';
    //            jsonString =jsonString.replace("'", "\\\\u0027")
    ObjectMapper mapper = new ObjectMapper();
    String partNumberList = "[{productId:AS101R}, {productId:09902007}, {productId:09902002}, {productId:09902005}]";
    partNumberList = partNumberList.replaceAll(":", ":\"").replaceAll("}", "\"}");
    System.out.println(partNumberList);
    mapper.configure(com.fasterxml.jackson.core.JsonParser.Feature.ALLOW_UNQUOTED_FIELD_NAMES, true);
    List<ProductDto> jsonToPersonList = null;
    jsonToPersonList = mapper.readValue(partNumberList, new TypeReference<List<ProductDto>>() {
    });
    System.out.println(jsonToPersonList);
}

Upvotes: -7

Perception
Perception

Reputation: 80603

If you have control over the ObjectMapper instance, then configure it to handle and generate JSON the way you want:

final ObjectMapper mapper = new ObjectMapper();
mapper.configure(JsonGenerator.Feature.QUOTE_FIELD_NAMES, false);
mapper.configure(JsonParser.Feature.ALLOW_UNQUOTED_FIELD_NAMES, true);

Upvotes: 40

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