CODEWITHSUNDEEP
androidopengl-es
Piotrek
Piotrek

Reputation: 11211

onTouchEvent in OpenGLRenderer?

I created a OpenGL Renderer

public class OpenGLRenderer implements Renderer {

And now I want to get data from onTouchEvent. Unfortunately, it doesn't work:

public boolean onTouchEvent(MotionEvent event){
    //eyeX += 0.2f;
    //eyeY = 0.2f;
    eyeZ -= 0.2f;
    Log.v("OpenGLRenderer", "TouchEvent works");
    return true;
}

When I change my class to:

public class OpenGLRenderer extends GLSurfaceView implements Renderer {

and my onTouchEvent function to:

@Override
public boolean onTouchEvent(MotionEvent event){
    //eyeX += 0.2f;
    //eyeY = 0.2f;
    eyeZ -= 0.2f;
    Log.v("OpenGLRenderer", "TouchEvent works");
    return true;
}

still not works :/ What's wrong?

Upvotes: 0

Views: 844

Answers (2)

harikrishnan
harikrishnan

Reputation: 1945

This is for MyGLSurfaceview class.. when you touch the screen, you will get the that position x,y position range.

@Override
public boolean onTouchEvent(MotionEvent ev) {

    // Normal touch
    xPosition = ev.getX();
    yPosition = ev.getY();

    switch (ev.getAction()) {

        case MotionEvent.ACTION_DOWN:{
            dx = ev.getX();
            dy = ev.getY();
        }

        return ;
    }
}

Upvotes: 0

Mohamed_AbdAllah
Mohamed_AbdAllah

Reputation: 5322

From the GLSurfaceView documentation: "When handling the event, you may need to communicate with the Renderer object that's running in the rendering thread."

Use queueEvent(Runnable) to pass the event to the rendering Thread:

@override
public boolean onTouchEvent(MotionEvent event){
queueEvent(new Runnable() {
                 // This method will be called on the rendering
                 // thread:
                 public void run() {
                     eyeZ -= 0.2f;
    Log.v("OpenGLRenderer", "TouchEvent works");
                 }});
return true;
}

Upvotes: 1

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