Reputation: 17234
I don't know a single thing of perl but from a big perl script, I managed to get the relevant parts and make a HTTP request. So, this perl code works perfectly.
#!/usr/bin/perl -w
use strict;
use LWP::UserAgent;
use HTTP::Request::Common;
my $ua = new LWP::UserAgent;
my $request = "X-CTCH-PVer: 0000001\r\n";
my $method_url = "http://localhost:8088/ctasd/GetStatus";
my $response = $ua->request (POST $method_url,Content => $request);
my $data = $response->status_line . "\n";
print $data;
print $response->content;
The above code outputs:
200 OK
X-CTCH-PVer: 0000001
From my understanding, it's doing a POST to a URL with the specified data. With that base, my python code looks like:
#!/usr/bin/python
import urllib
url = "http://localhost:8088/ctasd/GetStatus"
data = urllib.urlencode([("X-CTCH-PVer", "0000001")])
print urllib.urlopen(url, data).read()
But, this returns response as:
X-CTCH-Error: Missing protocol header "X-CTCH-PVer"
Please help me in making a Python equivalent of perl code.
Upvotes: 2
Views: 1175
Reputation: 17234
So, the actual thing was, the $request
in Perl was literally been sent as POST data without any change. Now I get why is the name content
in Perl.
#!/usr/bin/python
import urllib
url = "http://localhost:8088/ctasd/GetStatus"
print urllib.urlopen(url, "X-CTCH-PVer: 0000001").read()
Worked. I actually found out about this after capturing the traffic in both cases and analysing it in wireshark.
Upvotes: 2
Reputation: 4367
The error is because you are not sending the header, you are making/sending a urlencoded string, hence the function urllib.urlencode
Try setting the request with actual headers:
#!/usr/bin/python
import urllib2
request = urllib2.Request("http://localhost:8088/ctasd/GetStatus", headers={"X-CTCH-PVer" : "0000001"})
contents = urllib2.urlopen(request).read()
Upvotes: 0