CODEWITHSUNDEEP
c#propertygridicustomtypedescriptor
Asher Saban
Asher Saban

Reputation: 4803

how to customize PropertyInfo[] object in PropertyGrid C#

i have a class that is loaded dynamically and i don't know in advance how many (or of what type) properties it contains. i would like to load all its properties into a PropertyGrid in a way that it would display as it displays a regular class.

for instance, if this is my class: 

class TestPropertyObject
{
    [Category("Names")]
    [Description("Enter your name")]
    public string Name { get; set; }

    [Category("Numbers")]
    [Description("Enter your number")]
    public int Number { get; set; }
}

and i use reflection to generate an object and get its properties: 

PropertyInfo[] info = obj.GetType().GetProperties()

how do i display the properties in the PropertyGrid?
i already ready many times this article http://www.codeproject.com/Articles/4448/Customized-display-of-collection-data-in-a-Propert but i just can't seem to get it to work.

some guidance would be very much appreciated.

thanks!

Upvotes: 0

Views: 722

Answers (1)

Paritosh
Paritosh

Reputation: 2379

here is a solution, you just need the instance of the class.

        var OptionsPropertyGrid = new PropertyGrid();
        OptionsPropertyGrid.Size = new Size(300, 250);

        this.Controls.Add(OptionsPropertyGrid);

        TestPropertyObject appset = new TestPropertyObject();
        OptionsPropertyGrid.SelectedObject = appset;

This sample is assuming that you class's property is decorated with Category/description. let me know if I have misunderstood it.

Or by using dynamic object 

        var OptionsPropertyGrid = new PropertyGrid();
        OptionsPropertyGrid.Size = new Size(300, 250);

        this.Controls.Add(OptionsPropertyGrid);
        this.Text = "Options Dialog";
        string classname = "WindowsFormsApplication1.TestPropertyObject";
        var type1 = Type.GetType(classname);
        object obj = Activator.CreateInstance(type1);
        OptionsPropertyGrid.SelectedObject = obj;

Make sure you can be able get the namespace of the class.

Upvotes: 1

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