CODEWITHSUNDEEP
phpajaxjsonextjsresponse
ramiromd
ramiromd

Reputation: 2029

Extjs JSON response

I have a form, which sends data to the server. I process the form with a PHP script, which can return 3 differents JSON strings:

One

exit("{\"success\":\"false\", \"msg\":\"Las claves no cohinciden\"}");

Two

exit("{\"success\":\"false\", \"msg\":\"".$failure->getMessage()."\"}");

Three

exit("{\"success\":\"true\",\"msg\":\"El usuario: $nombreUsuario ha sido dado de alta correctamente.\"}");

The first and second strings, are errors to show. The third string is the normal case. When the script return some of these values, i catch the response with ExtJs do:

var respuesta = Ext.JSON.decode(response.responseText);

But, when do:

console.log(respuesta);

Firebug console says that "respuesta" are undefinied. Any idea ?

Upvotes: 1

Views: 3098

Answers (2)

ajay
ajay

Reputation: 1570

you can use this url for testing your Json code:

http://www.utilities-online.info/xmltojson/#.UNr9FhhQ-gY

Upvotes: 0

phpisuber01
phpisuber01

Reputation: 7715

When you are outputting JSON for using in AJAX, it's best to set the headers for JSON and return properly formatted JSON. In my below example, we create a normal PHP array with your response and convert it to JSON with json_encode().

Try it. I've had issues before with Javascript not taking a string in as JSON before without a proper content type and formatting.

<?php

$response = array("success" => "false", "msg" => "Las claves no cohinciden");

header("Content-type: application/json");
exit(json_encode($response));

?>

Optionally, if you have jQuery... You can do $.parseJSON('your string'); to output JSON from a string.

Upvotes: 2

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