CODEWITHSUNDEEP
batch-file
Sumedh
Sumedh

Reputation: 648

Need a little help filtering lines in batch

I have text file which contains the follwing

Pool        p c Dev   Dev             Total  Enabled     Used     Free   a   b
------------ - - ----- ------------ -------- -------- -------- -------- --- ---
FC100        T F FBA   RAID-3(1+1)   13849.1  13849.1  13119.4   7292.0   0 Ena
SATA500      T S FBA   RAID-3(1+1)   50019.2  50019.2  46974.5   3044.9 Ena   0


I want to display extract FC100 and SATA500 from the file because those two lines contain "Ena". I have very little batch script experience so with my limited knowledge I came up with following script. 

@ECHO OFF
setlocal enabledelayedexpansion

FOR /F "tokens=1,* delims= " %%a in (list.txt) DO (
    if "%%b" NEQ "" (

        set string=%%b
        set substring= Ena

        echo !string! |findstr "!substring!" > nul
        if errorlevel 1 (
            rem echo !SubString!
        ) else (
            echo %%a
        )
    )
)

What is happening with the above code is that I am getting the required output but I am also getting Pool because the line contains Ena in Enabled. How do extract lines which only contain Ena and not match with Enabled.

Current Output

Pool
FC100
SATA500

I tried to use some regex magic with findstr but its not working out for me. Note - I can solve this problem in Perl but unfortunately I cannot install Perl on the system so I have to do this in batch.

Upvotes: 2

Views: 364

Answers (4)

Stephan
Stephan

Reputation: 56238

replace

echo !string! |findstr "!substring!" > nul

with 

echo !string! |findstr "!substring!" |findstr /v "Enabled" > nul

or even simpler:

echo !string! |findstr "Ena" |findstr /v "Enabled" > nul

first findstr will include all lines with "Ena", second findstr /v will exclude all lines with "Enabled".

Upvotes: 0

Aacini
Aacini

Reputation: 67326

@echo off
for /F "skip=1" %%a in ('findstr /C:" Ena" list.txt') do (
   echo %%a
)

EDIT: New solution that seek for lines precisely with "Ena" string in any part

@echo off
for /F %%a in ('findstr /R /C:"\<Ena\>" list.txt') do (
   echo %%a
)

Upvotes: 3

Andriy M
Andriy M

Reputation: 77737

You probably want to match Ena as a whole word. To do that, you can surround your search term with \< and \>, i.e. change the substring assignment like this:

set "substring=\<Ena\>"

And by the way, there's probably no need to assign substring to the same value at every iteration of the loop. You can assign it just once before the loop.

Upvotes: 2

tcb
tcb

Reputation: 2824

Try this:

set substring="Ena[^a-zA-Z]"

[^a-zA-Z] instructs findstr not to use strings which contain letters after Ena.

Upvotes: 0

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