Reputation: 574
On my system errno
defined as:
int * __error(void);
#define errno (* __error())
I understand errno
is a macro and expands to * __error()
function:
I searched everywhere (source on my system) but I can't find the definition of the __error()
function, can someone show/explain what would/should be the definition of it?
How the expression errno = 0
works with the above definition (Assigning 0
to a function?)? Does errno = 0
expands to * __error() = 0
?
Thanks
Upvotes: 4
Views: 3095
Reputation: 182865
The __error
function returns a pointer to the errno
variable for the calling thread. The errno
macro dereferences that pointer, resulting in an lvalue that can appear on either side of an equals sign.
To answer your questions:
The function determines the correct address for the errno
variable for that specific thread. Each thread gets its own.
Yes, it becomes (* __error()) = 0;
which assigns 0
to that thread's errno
variable.
Upvotes: 9