CODEWITHSUNDEEP
csssvggradientlinear-gradients
Hrishikesh -Rishi- Choudhari
Hrishikesh -Rishi- Choudhari

Reputation: 12427

SVG gradient using CSS

I'm trying to get a gradient applied to an SVG rect element.

Currently, I'm using the fill attribute. In my CSS file:

rect {
    cursor: pointer;
    shape-rendering: crispEdges;
    fill: #a71a2e;
}

And the rect element has the correct fill color when viewed in the browser.

However, I'd like to know if I can apply a linear gradient to this element?

Upvotes: 151

Views: 286574

Answers (6)

Roland Gautier
Roland Gautier

Reputation: 345

Thank you everyone, for all your precise replys.

Using the svg in a shadow dom, I add the 3 linear gradients I need within the svg, inside a . I place the css fill rule on the web component and the inheritance od fill does the job.

    <svg viewbox="0 0 512 512" xmlns="http://www.w3.org/2000/svg">
      <path
        d="m258 0c-45 0-83 38-83 83 0 45 37 83 83 83 45 0 83-39 83-84 0-45-38-82-83-82zm-85 204c-13 0-24 10-24 23v48c0 13 11 23 24 23h23v119h-23c-13 0-24 11-24 24l-0 47c0 13 11 24 24 24h168c13 0 24-11 24-24l0-47c0-13-11-24-24-24h-21v-190c0-13-11-23-24-23h-123z"></path>
    </svg>
    
    <svg height="0" width="0">
      <defs>
        <linearGradient id="lgrad-p" gradientTransform="rotate(75)"><stop offset="45%" stop-color="#4169e1"></stop><stop offset="99%" stop-color="#c44764"></stop></linearGradient>
        <linearGradient id="lgrad-s" gradientTransform="rotate(75)"><stop offset="45%" stop-color="#ef3c3a"></stop><stop offset="99%" stop-color="#6d5eb7"></stop></linearGradient>
        <linearGradient id="lgrad-g" gradientTransform="rotate(75)"><stop offset="45%" stop-color="#585f74"></stop><stop offset="99%" stop-color="#b6bbc8"></stop></linearGradient>
      </defs>
    </svg>
    
    <div></div>

    <style>
      :first-child {
        height:150px;
        width:150px;
        fill:url(#lgrad-p) blue;
      }
      div{
        position:relative;
        width:150px;
        height:150px;
        fill:url(#lgrad-s) red;
      }
    </style>
    <script>
      const shadow = document.querySelector('div').attachShadow({mode: 'open'});
      shadow.innerHTML="<svg viewbox=\"0 0 512 512\">\
        <path d=\"m258 0c-45 0-83 38-83 83 0 45 37 83 83 83 45 0 83-39 83-84 0-45-38-82-83-82zm-85 204c-13 0-24 10-24 23v48c0 13 11 23 24 23h23v119h-23c-13 0-24 11-24 24l-0 47c0 13 11 24 24 24h168c13 0 24-11 24-24l0-47c0-13-11-24-24-24h-21v-190c0-13-11-23-24-23h-123z\"></path>\
      </svg>\
      <svg height=\"0\">\
      <defs>\
        <linearGradient id=\"lgrad-s\" gradientTransform=\"rotate(75)\"><stop offset=\"45%\" stop-color=\"#ef3c3a\"></stop><stop offset=\"99%\" stop-color=\"#6d5eb7\"></stop></linearGradient>\
        <linearGradient id=\"lgrad-g\" gradientTransform=\"rotate(75)\"><stop offset=\"45%\" stop-color=\"#585f74\"></stop><stop offset=\"99%\" stop-color=\"#b6bbc8\"></stop></linearGradient>\
      </defs>\
    </svg>\
    ";
    </script>

The first one is normal SVG, the second one is inside a shadow dom.

Upvotes: 7

kumarharsh
kumarharsh

Reputation: 19609

Building on top of what Finesse wrote, here is a simpler way to target the svg and change it's gradient.

This is what you need to do:

  1. Assign classes to each color stop defined in the gradient element.
  2. Target the css and change the stop-color for each of those stops using plain classes.
  3. Win!

Some benefits of using classes instead of :nth-child is that it'll not be affected if you reorder your stops. Also, it makes the intent of each class clear - you'll be left wondering whether you needed a blue color on the first child or the second one.

I've tested it on all Chrome, Firefox and IE11:

.main-stop {
  stop-color: red;
}
.alt-stop {
  stop-color: green;
}
<svg class="green" width="100" height="50" version="1.1" xmlns="http://www.w3.org/2000/svg">
  <linearGradient id="gradient">
    <stop class="main-stop" offset="0%" />
    <stop class="alt-stop" offset="100%" />
  </linearGradient>
  <rect width="100" height="50" fill="url(#gradient)" />
</svg>

See an editable example here: https://jsbin.com/gabuvisuhe/edit?html,css,output

Upvotes: 42

Maciej Kwas
Maciej Kwas

Reputation: 6419

2019 Answer

With brand new css properties you can have even more flexibility with variables aka custom properties

.shape {
  width:500px;
  height:200px;
}

.shape .gradient-bg {
  fill: url(#header-shape-gradient) #fff;
}

#header-shape-gradient {
  --color-stop: #f12c06;
  --color-bot: #faed34;
}
<svg viewBox="0 0 100 100" xmlns="http://www.w3.org/2000/svg" preserveAspectRatio="none" class="shape">
  <defs>
    <linearGradient id="header-shape-gradient" x2="0.35" y2="1">
        <stop offset="0%" stop-color="var(--color-stop)" />
        <stop offset="30%" stop-color="var(--color-stop)" />
        <stop offset="100%" stop-color="var(--color-bot)" />
      </linearGradient>
  </defs>
  <g>
    <polygon class="gradient-bg" points="0,0 100,0 0,66" />
  </g>
</svg>

Just set a named variable for each stop in gradient and then customize as you like in css. You can even change their values dynamically with javascript, like:

document.querySelector('#header-shape-gradient').style.setProperty('--color-stop', "#f5f7f9");

Upvotes: 71

axelparatre
axelparatre

Reputation: 81

Here is how to set a linearGradient on a target element: 

<style type="text/css">
    path{fill:url('#MyGradient')}
</style>
<defs>
    <linearGradient id="MyGradient">
        <stop offset="0%" stop-color="#e4e4e3" ></stop>
        <stop offset="80%" stop-color="#fff" ></stop>
    </linearGradient>
</defs>

Upvotes: -1

Finesse
Finesse

Reputation: 10801

Here is a solution where you can add a gradient and change its colours using only CSS:

// JS is not required for the solution. It's used only for the interactive demo.
const svg = document.querySelector('svg');
document.querySelector('#greenButton').addEventListener('click', () => svg.setAttribute('class', 'green'));
document.querySelector('#redButton').addEventListener('click', () => svg.setAttribute('class', 'red'));
svg.green stop:nth-child(1) {
  stop-color: #60c50b;
}
svg.green stop:nth-child(2) {
  stop-color: #139a26;
}

svg.red stop:nth-child(1) {
  stop-color: #c84f31;
}
svg.red stop:nth-child(2) {
  stop-color: #dA3448;
}
<svg class="green" width="100" height="50" version="1.1" xmlns="http://www.w3.org/2000/svg">
  <linearGradient id="gradient">
    <stop offset="0%" />
    <stop offset="100%" />
  </linearGradient>
  <rect width="100" height="50" fill="url(#gradient)" />
</svg>

<br/>
<button id="greenButton">Green</button>
<button id="redButton">Red</button>

Upvotes: 15

Thomas W
Thomas W

Reputation: 15371

Just use in the CSS whatever you would use in a fill attribute. Of course, this requires that you have defined the linear gradient somewhere in your SVG.

Here is a complete example:

rect {
    cursor: pointer;
    shape-rendering: crispEdges;
    fill: url(#MyGradient);
}
<svg width="100" height="50" version="1.1" xmlns="http://www.w3.org/2000/svg">
      <style type="text/css">
        rect{fill:url(#MyGradient)}
      </style>
      <defs>
        <linearGradient id="MyGradient">
          <stop offset="5%" stop-color="#F60" />
          <stop offset="95%" stop-color="#FF6" />
        </linearGradient>
      </defs>
      
      <rect width="100" height="50"/>
    </svg>

Upvotes: 140

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