Reputation: 283
Now I can convert a hex string to rgb color like this:
// Input is without the # ie : white = FFFFFF
+ (UIColor *)colorWithHexString:(NSString *)hexString
{
unsigned int hex;
[[NSScanner scannerWithString:hexString] scanHexInt:&hex];
int r = (hex >> 16) & 0xFF;
int g = (hex >> 8) & 0xFF;
int b = (hex) & 0xFF;
return [UIColor colorWithRed:r / 255.0f
green:g / 255.0f
blue:b / 255.0f
alpha:1.0f];
}
bu how can I convert rgb to hex string?
Upvotes: 24
Views: 22156
Reputation: 705
Objective-c UIColor category. This method can avoid situations like #FFFF00000000
- (id)hexString {
CGFloat r, g, b, a;
[self getRed:&r green:&g blue:&b alpha:&a];
int rgb = (int)(r * 255.0f)<<16 | (int)(g * 255.0f)<<8 | (int)(b * 255.0f)<<0;
if (a < 1) {
rgb = (int)(a * 255.0f)<<24 | (int)(r * 255.0f)<<16 | (int)(g * 255.0f)<<8 | (int)(b * 255.0f)<<0;
}
return [NSString stringWithFormat:@"#%06x", rgb];
}
Upvotes: 0
Reputation: 4946
Use this Extension of UIColor to get hexString from it.
extension UIColor {
func toHexString() -> String {
var r:CGFloat = 0
var g:CGFloat = 0
var b:CGFloat = 0
var a:CGFloat = 0
getRed(&r, green: &g, blue: &b, alpha: &a)
let rgb:Int = (Int)(r*255)<<16 | (Int)(g*255)<<8 | (Int)(b*255)<<0
return String(format:"#%06x", rgb)
}
}
Upvotes: 20
Reputation: 6365
Anoop answer is not correct as if you try it with [UIColor blackColor]
it will return green color's hex string.
Reason is system is cleaver enough to save memory it will set
For black color
component[0] = 0 (r=0,g=0,b=0) and
component[1] = 1 (a=1).
For white color
component[0] = 1 (r=1,g=1,b=1) and
component[1] = 1 (a=1).
UIColor+Utility.h
@interface UIColor (Utility)
/**
Return representaiton in hex
*/
-(NSString*)representInHex;
@end
UIColor+Utility.m
@implementation UIColor (Utility)
-(NSString*)representInHex
{
const CGFloat *components = CGColorGetComponents(self.CGColor);
size_t count = CGColorGetNumberOfComponents(self.CGColor);
if(count == 2){
return [NSString stringWithFormat:@"#%02lX%02lX%02lX",
lroundf(components[0] * 255.0),
lroundf(components[0] * 255.0),
lroundf(components[0] * 255.0)];
}else{
return [NSString stringWithFormat:@"#%02lX%02lX%02lX",
lroundf(components[0] * 255.0),
lroundf(components[1] * 255.0),
lroundf(components[2] * 255.0)];
}
}
@end
Upvotes: 9
Reputation: 61
This is the code that I used in Swift, please be aware that this seems to work fine when you send it a UIColor created with the rgba values, but returns some strange results when sending pre-defined colours like UIColor.darkGrayColor()
func hexFromUIColor(color: UIColor) -> String
{
let hexString = String(format: "%02X%02X%02X",
Int(CGColorGetComponents(color.CGColor)[0] * 255.0),
Int(CGColorGetComponents(color.CGColor)[1] *255.0),
Int(CGColorGetComponents(color.CGColor)[2] * 255.0))
return hexString
}
Upvotes: 6
Reputation: 46533
Use this method :
- (NSString *)hexStringForColor:(UIColor *)color {
const CGFloat *components = CGColorGetComponents(color.CGColor);
CGFloat r = components[0];
CGFloat g = components[1];
CGFloat b = components[2];
NSString *hexString=[NSString stringWithFormat:@"%02X%02X%02X", (int)(r * 255), (int)(g * 255), (int)(b * 255)];
return hexString;
}
Upvotes: 44