CODEWITHSUNDEEP
pythonceleryweb2py
blueFast
blueFast

Reputation: 44471

Any clever way to unescape data from JSON string?

I am sending some jsonrpc requests to a web2py server, with a celery backend. Sometimes, I get errors which I want to analyze. The errors come escaped in the jsonrpc reply, so they are not easy to understand. I get something like this:

{"version": "1.1", "id": "ID4", "error": {"message": "TypeError: 'NoneType' object does not support item assignment", "code": 100, "data": ["  File \"/home/myuser1/tmp/web2py/gluon/tools.py\", line 4068, in serve_jsonrpc\n    s = methods[method](*params)\n", "  File \"/home/myuser1/tmp/web2py/applications/mycompany_portal/controllers/activity.py\", line 66, in get_cdr_page\n    invalidate_cache = pars['invalidate_cache'], use_long_polling = pars['use_long_polling'])\n", "  File \"/home/myuser1/projects/new-mycompany-portal/python_modules/pmq_client.py\", line 85, in get_page\n    res = result.get(timeout=10)\n", "  File \"/home/myuser1/.virtualenvs/python2.7.2-mycompany1/lib/python2.7/site-packages/celery/result.py\", line 119, in get\n    interval=interval)\n", "  File \"/home/myuser1/.virtualenvs/python2.7.2-mycompany1/lib/python2.7/site-packages/celery/backends/amqp.py\", line 138, in wait_for\n    raise self.exception_to_python(meta['result'])\n"], "name": "JSONRPCError"}}

What I want is to get the error.data part of the jsonrpc reply, unescape it and display it as a stacktrace. I can do it manually (change \" -> " and process the \n), but I would like to avoid reinventing the wheel here.

Upvotes: 5

Views: 5937

Answers (2)

user1284631
user1284631

Reputation: 4616

Re-edit:

Use:

unquote

http://docs.python.org/2/library/urllib.html#urllib.unquote

or

unquote_plus

http://docs.python.org/2/library/urllib.html#urllib.unquote_plus

for unescape-ing HTTP-like data (ie. percentage-escaping)

See this question and answers for more info:

Unescape Python Strings From HTTP

And, for unescape-ing regular escaped symbols (ie. backslashes), use .decode() (counterpart of .encode()). See these answers:

https://stackoverflow.com/a/10944959/1284631

https://stackoverflow.com/a/9340191/1284631

Upvotes: 0

Pavel Anossov
Pavel Anossov

Reputation: 62948

Is this raw unparsed JSON? Parse it as JSON:

import json
print ''.join(json.loads(yourstring)['error']['data'])

Upvotes: 3

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