CODEWITHSUNDEEP
cmemory
Tom
Tom

Reputation: 9643

c - allocate memory to an array of pointers to functions

I want my function to create an array and allocate memory for n pointers to functions (for example, functions that have no parameters and return int) and to return a pointer to that array.

I tried doing:

void* f(int n){
   return calloc(int (*arrayName[])(void),n);
}

But i'm getting a syntax error. I'm pretty new to c and i tried to dig for an hour how to solve this issue with no success. using the man page i figured calloc is the way to go but i might be wrong.

Upvotes: 1

Views: 194

Answers (2)

user529758
user529758

Reputation:

Or if you don't want a typedef (hint: you still do want a typedef, just for completeness): wrap the type in a sizeof():

return calloc(n, sizeof(int (*)(void)));

Upvotes: 2

Kerrek SB
Kerrek SB

Reputation: 476980

Make your life easier and use typedefs:

typedef int (*fp)();

fp * f(size_t n)
{
    return calloc(n, sizeof(fp));
}

The hand-rolled declaration: int (*f(size_t n))()

Upvotes: 7

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