CODEWITHSUNDEEP
pythonoopintrospectionclass-method
tadasajon
tadasajon

Reputation: 14864

How to obtain the Class name from within a @classmethod?

I have the following code:

class ObjectOne(object):
    @classmethod
    def print_class_name(cls):
        print cls.__class__.__name__

    def print_class_name_again(self):
        print self.__class__.__name__

if __name__ == '__main__':
    obj_one = ObjectOne()
    obj_one.print_class_name()
    obj_one.print_class_name_again()

The output is:

type
ObjectOne

I would like the output to be:

ObjectOne
ObjectOne

But I would like to keep test_cls as a class method via the @classmethod decorator.

How can I accomplish this?

Upvotes: 51

Views: 49096

Answers (3)

Wil
Wil

Reputation: 380

I had a similar question and wantend to get the class name for logging and the function/method name. 

__name__ :  gives the program name
__class__.__name__ gives the class name

inspect.stack()[0][3] gives the module name. (you have to import inspect).

Cheers

Upvotes: 16

BrenBarn
BrenBarn

Reputation: 251548

A classmethod receives the class as its argument. That's why you're calling it cls. Just do cls.__name__.

Upvotes: 59

Matti Virkkunen
Matti Virkkunen

Reputation: 65166

It's cls.__name__. cls already points to the class, and now you're getting the name of its class (which is always type).

Upvotes: 18

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