CODEWITHSUNDEEP
if-statementpython-2.7
Bill Rosmus
Bill Rosmus

Reputation: 3011

python conditional issue (2.7)

cccI have a python script that is driving me nuts. Here is the offending code... the code in the if statement is not running, can someone suggest why?:

print("refresh_type is: " + refresh_type)

if (refresh_type == "update"):
    print("hello world")
    cmd = 'sudo svn %s --username %s --password %s  %s' % ('up', un, pw, working_path)
    print("command is: " + str(cmd))
elif(refresh_type == 'checkout' or refresh_type == 'co'):
    cmd = 'sudo svn %s --username %s --password %s  %s %s' % (refreshType, un, pw, rc_service_url, working_path)

print('username = ' + credentials['un'])
print('password = ' + credentials['pw'])
print("working path = " + working_path)

Here are the outputs of the print statements:

refresh_type is: 'update'
username = 'cccc'
password = 'vvvvv'
working path = '/home/ubuntu/workingcopy/rc_service'

Upvotes: 1

Views: 147

Answers (1)

Martijn Pieters
Martijn Pieters

Reputation: 1121316

Your refresh_type value is not update, it's 'update'. The rest of your variables suffer from the same ailment, they have quotes as part of the string value.

Use print "refresh_type is:", repr(refresh_type) as a diagnostic aid in this.

You could use:

if refresh_type == "'update'":

but you have a more fundamental problem, one where you end up with extra quotes in your string values.

To illustrate, a short Python interpreter session:

>>> print 'update'
update
>>> print "'update'"
'update'
>>> "'update'" == 'update'
False
>>> foo = "'update'"
>>> print repr(foo)
"'update'"

Upvotes: 4

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