CODEWITHSUNDEEP
phpfunction
janenz00
janenz00

Reputation: 3310

PHP Call to undefined function

I am trying to call a function from another function. I get an error:

Fatal error: Call to undefined function getInitialInformation() 
in controller.php on line 24

controller.php file:

require_once("model/model.php"); 

function intake() {
    $info = getInitialInformation($id); //line 24
}

model/model.php

function getInitialInformation($id) {
    return $GLOBALS['em']->find('InitialInformation', $id);
}

Things already tried:

  1. Verified that the require_once works, and the file exists in the specified location.
  2. Verified that the function exists in the file.

I am not able to figure this out. Am I missing something here?

Upvotes: 41

Views: 321204

Answers (8)

user2984447
user2984447

Reputation: 79

Disclaimer: Am not an expert on PHP. I had a similar issues while upgrading PHP version for apache2, tried all the suggested solutions but didn't help. Finally found that the php-fpm version enabled (had to do something like -sudo a2enmod php7.4) and the one present in /etc/apache2 php.ini PHP version were different. Once these were synchronized, the error went away.

Upvotes: 0

user8136352
user8136352

Reputation: 11

Presently I am working on web services where my function is defined and it was throwing an error undefined function.I just added this in autoload.php in codeigniter

$autoload['helper'] = array('common','security','url');

common is the name of my controller.

Upvotes: 0

epeleg
epeleg

Reputation: 10945

This is obviously not the case in this Q, but since I got here following the same error message I though I would add what was wrong with my code and maybe it will help some one else:

I was porting code from JS to PHP and ended up having a class with some public method. The code that was calling the class (being code that originated from JS) looked something like:

$myObject.method(...)

this is wrong because in PHP it should look like this:

$myObject->method(...)

and it also resulted with "PHP Call to undefined function".

change to use -> and the problem was solved.

Upvotes: 1

Asier Arizti
Asier Arizti

Reputation: 11

I happened that problem on a virtual server, when everything worked correctly on other hosting. After several modifications I realized that I include or require_one works on all calls except in a file. The problem of this file was the code < ?php ? > At the beginning and end of the text. It was a script that was only < ?, and in that version of apache that was running did not work

Upvotes: 1

JRivero
JRivero

Reputation: 91

Many times the problem comes because php does not support short open tags in php.ini file, i.e:

<?
   phpinfo();
?>

You must use:

<?php
   phpinfo();
?>

Upvotes: 8

janenz00
janenz00

Reputation: 3310

This was a developer mistake - a misplaced ending brace, which made the above function a nested function.

I see a lot of questions related to the undefined function error in SO. Let me note down this as an answer, in case someone else have the same issue with function scope.

Things I tried to troubleshoot first:

  1. Searched for the php file with the function definition in it. Verified that the file exists.
  2. Verified that the require (or include) statement for the above file exists in the page. Also, verified the absolute path in the require/include is correct.
  3. Verified that the filename is spelled correctly in the require statement.
  4. Echoed a word in the included file, to see if it has been properly included.
  5. Defined a separate function at the end of file, and called it. It worked too.

It was difficult to trace the braces, since the functions were very long - problem with legacy systems. Further steps to troubleshoot were this:

  1. I already defined a simple print function at the end of included file. I moved it to just above the "undefined function". That made it undefined too.

  2. Identified this as some scope issue.

  3. Used the Netbeans collapse (code fold) feature to check the function just above this one. So, the 1000 lines function above just collapsed along with this one, making this a nested function.

  4. Once the problem identified, cut-pasted the function to the end of file, which solved the issue.

Upvotes: 30

Eric Leschinski
Eric Leschinski

Reputation: 154103

How to reproduce the error, and how to fix it:

  1. Put this code in a file called p.php:

    <?php
class yoyo{
    function salt(){
    }
    function pepper(){
        salt();
    }
}
$y = new yoyo();
$y->pepper();
?>

  2. Run it like this:

    php p.php

  3. We get error:

    PHP Fatal error:  Call to undefined function salt() in 
/home/el/foo/p.php on line 6

  4. Solution: use $this->salt(); instead of salt();

    So do it like this instead:

    <?php
class yoyo{
    function salt(){
    }
    function pepper(){
        $this->salt();
    }
}
$y = new yoyo();
$y->pepper();

?>

If someone could post a link to why $this has to be used before PHP functions within classes, yeah, that would be great.

Upvotes: 92

Jonathan Amend
Jonathan Amend

Reputation: 12815

Your function is probably in a different namespace than the one you're calling it from.

http://php.net/manual/en/language.namespaces.basics.php

Upvotes: 5

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