Reputation: 117
I am looking for the script which will search the largest time value from the mysql returned row. Mysql returned row like:
(123, 'new', datetime.datetime(2013, 1, 2, 16, 6, 21))
(122, 'old', datetime.datetime(2012, 12, 3, 18, 08, 36))
(125, 'new', datetime.datetime(2012, 12, 13, 20, 18, 16))
i tried with:
value = 0
for row in rows:
if row[2] > value:
value = row
print value
if we print the row[2] value that will show like that
for row in rows:
print row[2]
output: 2013-01-02 16:06:21
2012-12-03 18:08:36
2013-12-13 20:18:16
Upvotes: 1
Views: 112
Reputation: 17042
Anders Johansson answers your question neatly.
However, you could also avoid the need to do this in Python to begin with, by simply requesting only that line of data. A SQL statement like:
SELECT DateTime FROM MyTable
ORDER BY CASE WHEN Status IS 'new' THEN 1 ELSE 0 END DESC, DateTime DESC LIMIT 1;
would achieve what you're trying to do, and give you only that one data point.
SELECT mydate FROM MyTable
WHERE type=4
ORDER BY FIELD(status, 'new', 'waited', 'old'), mydate DESC
LIMIT 1;
Upvotes: 1