CODEWITHSUNDEEP
c#.netxpathumbraco
Jeft Lebowski
Jeft Lebowski

Reputation: 71

Umbraco - GetMedia does not return the correct url

I'm trying to redirect to the media url, but using the code blow, results in the full url concatenated by the size of the media.

So for example the url returns /media/123/example.pdfpdf4000 

XPathNodeIterator xName = umbraco.library.GetMedia(Convert.ToInt32(pdfid), false);
string url = xName.Current.Value;
Response.Redirect("~/"+ url);

What is happening?

Upvotes: 2

Views: 4231

Answers (3)

Aximili
Aximili

Reputation: 29484

To get the media file URL, it's simply

new Media(mediaId).getProperty("umbracoFile").Value.ToString()

Upvotes: 0

Ian Grainger
Ian Grainger

Reputation: 5526

I was just looking for how to do this, and umbraco now includes uQuery to get data like this easier, so to answer your question you could use:

Media pdf = umbraco.uQuery.GetMedia(pdfId);
Response.Redirect(pdf.GetProperty<string>("umbracoFile"));

Just a note: If it was an image media item (rather than a file) it'd be even easier:

Media img = umbraco.uQuery.GetMedia(imgId);
imgTag.ImageUrl = img.GetImageUrl();

Not sure why uQuery doesn't include GetFileUrl() but GetProperty<string>() seems nicer than using the xpath iterator yourself.

Upvotes: 3

Digbyswift
Digbyswift

Reputation: 10400

There is a solution explained here and also here. But, in essence you can create a method as below to fix the issue:

public string getImage(int ImageID)
{
    XPathNodeIterator xn = umbraco.library.GetMedia(ImageID, false);
    xn.MoveNext();

    XPathNodeIterator xn2 = xn.Current.Select("data[@alias='umbracoFile']");
    xn2.MoveNext();
    return xn2.Current.Value;
}

Upvotes: 2

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