CODEWITHSUNDEEP
cpointers
Ruhama Ski
Ruhama Ski

Reputation: 9

compare pointer to character

I tried to write this thing in C:

(*(result+1))!="\0"

The compiler said:

Possible assignment in condition (*(result+1))=!"\0"

What is the problem?

Upvotes: 0

Views: 102

Answers (2)

Carl Norum
Carl Norum

Reputation: 224854

Comparisons in C use the == operator. The single = is an assignment. Besides that, you're trying to compare a pointer to an integer. The code you have is:

(*(result+1))=!"\0"

In that expression, !"\0" is equal to 0, so your code is really doing:

(*(result+1))=0

And that's probably not what you want. For sure it doesn't match what you have there in your "I'm trying to write this expression" example. I think what you are trying to do is:

(*(result+1)) != '\0'

Using the != "not equal to" operator. It just looks like you have written =! instead. Probably just a typo. Note that I changed the double quotes to single quotes to correct your expression, too.

Editorial note - you don't need the operator at all. Your expression is equal to:

*(result + 1)

Which would have saved you the trouble in the first place.

Upvotes: 7

octopusgrabbus
octopusgrabbus

Reputation: 10685

If you are indeed performing a comparison and not an assignment, you need == instead of =; that is why you're getting the possible assignment message.

Upvotes: 1

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