CODEWITHSUNDEEP
phpmysqlinsert-updatelastinsertid
Val
Val

Reputation: 413

Using an insert id from first of three queries in php

I want to store the data from several curl calls to an initial table, but last insert id is inserting wrong info

Query 1 inserts data into table

table1

   id name      email      valuereturn
   1   val     [email protected]       0

I then post data 3 times to my system and log it

table2

    id  name    system  valuereturn
    1   val      5       0
    2   val      0       0
    3   val      0       0

the max value returned from my system i want to update table 1

update table1 
set valuereturn = '5' 
where id = LAST_INSERT_ID()

does not work because last insert id is 3 from table2, how can I use something like last_insert_id(Table1)?

i want to update my

Upvotes: 1

Views: 116

Answers (3)

Praveen Kumar Purushothaman
Praveen Kumar Purushothaman

Reputation: 167162

In PHP I assume you use the following code:

<?php
  connect_db();
  insert_first_query_to_table1();
  insert_second_query_to_table2();
  update_query_setting(last_insert_id());
?>

If that's the case, I suggest you to use a temp variable to store the last_insert_id.

<?php
  connect_db();
  insert_first_query_to_table1();
  $setVal = last_insert_id();
  insert_second_query_to_table2();
  update_query_setting($setVal);
?>

Hope this helps.

PS: This is a pseudo code!

Upvotes: 1

AndreKR
AndreKR

Reputation: 33658

Well, you can't. You have to retrieve and remember it in a PHP variable.

Or go for Saharsh's solution and remember it in a MySQL variable.

Upvotes: 1

Saharsh Shah
Saharsh Shah

Reputation: 29051

Store that LAST_INSERT_ID() of table1 in a variable and than use that variable in update query.

INSERT INTO table1(name) values ('Saharsh');
SELECT LAST_INSERT_ID() INTO @table1Id;

INSERT INTO table2(name, table1id) values ('Saharsh', @table1Id);
UPDATE table1 SET valuereturn = '5' WHERE id = @table1Id;

Upvotes: 1

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