CODEWITHSUNDEEP
pythondirectoryorganization
ntoscano
ntoscano

Reputation: 67

working with directories | python

i'm writing code to organize +40G's of music, right now all the files are in one big folder, my goal is to have a directory for each artist. right now, i've been able to extract the artist info, and make a directory with it, but an issue that i've found is that if i have two files with the same artist info, i am given the error of two folders with the same name.

I need help with preventing the second folder from happening.

import os #imports os functions
import eyed3 #imports eyed3 functions

root_folder = '/Users/ntoscano/desktop/mp3-organizer'

files = os.listdir(root_folder) #lists all files in specified directory
if not files[1].endswith('.mp3'):
    pass #if the file does not end with ".mp3" it does not load it into eyed3

for file_name in files:
    if file_name.endswith('.mp3'): #if file ends with ".mp3" it continues onto the next line

        abs_location = '%s/%s' % (root_folder, file_name)

        song_info = eyed3.load(abs_location) #loads each file into eyed3 and assignes the return value to song_info
        if song_info is None:
            print 'Skippig %s' % abs_location
            continue
        os.mkdir(os.path.expanduser('~/Desktop/mp3-organizer/%s' % song_info.tag.artist))
        print song_info
        print song_info.tag.artist
    else:
        pass

Upvotes: 1

Views: 130

Answers (1)

Tim
Tim

Reputation: 12174

Wrap the mkdir in a try/except and catch the exception raised when the directory exists. Make sure to also import the errno module.

try:
    os.mkdir(os.path.expanduser('~/Desktop/mp3-organizer/%s' % song_info.tag.artist))
except OSError as e:
    if e.errno != errno.EEXIST:
        raise

You could also check if the directory exists using os.path.isdir(), but this introduces a race condition.

Upvotes: 2

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